hackrf OOK算法简单数据分析(傅里叶计算)

python 复制代码
import numpy as np



def savedata():
    data = []
    i = 0
    c = 0
    while c < 100:
        if c == 50:
            data.append((127.5*np.sin(2*np.pi/(32000/1000))))  # 当数据为 1 时
            data.append((127.5*np.cos(2*np.pi/(32000/1000))))
        data.append((i*127.5*np.sin(2*np.pi/(32000/1000))))   # 当数据为 0 时
        data.append((i*127.5*np.cos(2*np.pi/(32000/1000))))
        i += 1
        c += 1
        i /= (32000/1000)
    np.save("1",data)
    return 

def loaddata():
    data = np.load("1.npy")
    print(data)

savedata()
loaddata()
python 复制代码
[  0.           0.           0.777313     3.90781635   0.80160403
   4.02993561   0.80236313   4.03375184   0.80238685   4.0338711
   0.80238759   4.03387482   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
  24.87401606 125.05012325   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494   0.80238761   4.03387494   0.80238761
   4.03387494   0.80238761   4.03387494   0.80238761   4.03387494
   0.80238761   4.03387494]

4.03387494 为虚拟信号 也就是在gnuradio里需要虚拟信号加上数据信号

当 c = 50 时 我们让信号竖起 在没有数据时 信号是平的

相关推荐
汉克老师4 小时前
第十四届蓝桥杯青少组C++选拔赛[2023.2.12]第二部分编程题(5、机甲战士)
c++·算法·蓝桥杯·01背包·蓝桥杯c++·c++蓝桥杯
Mr_Xuhhh5 小时前
项目需求分析(2)
c++·算法·leetcode·log4j
c++bug6 小时前
六级第一关——下楼梯
算法
Morri36 小时前
[Java恶补day53] 45. 跳跃游戏Ⅱ
java·算法·leetcode
林木辛6 小时前
LeetCode热题 15.三数之和(双指针)
算法·leetcode·双指针
AndrewHZ6 小时前
【3D算法技术】blender中,在曲面上如何进行贴图?
算法·3d·blender·贴图·三维建模·三维重建·pcg
Jared_devin6 小时前
二叉树算法题—— [蓝桥杯 2019 省 AB] 完全二叉树的权值
数据结构·c++·算法·职场和发展·蓝桥杯
AI 嗯啦8 小时前
数据结构深度解析:二叉树的基本原理
数据结构·算法
和光同尘@8 小时前
66. 加一 (编程基础0到1)(Leetcode)
数据结构·人工智能·算法·leetcode·职场和发展
CHEN5_028 小时前
leetcode-hot100 11.盛水最多容器
java·算法·leetcode