python
class Solution:
def minDistance(self, word1: str, word2: str) -> int:
m=len(word1)
n=len(word2)
dp=[[0 for j in range(n+1)] for i in range(m+1)]
for i in range(1,m+1):
dp[i][0]=i
for j in range(1,n+1):
dp[0][j]=j
for i in range(1,m+1):
for j in range(1,n+1):
if word1[i-1]==word2[j-1]:
dp[i][j]=dp[i-1][j-1]
else:
dp[i][j]=min(dp[i-1][j-1],dp[i-1][j],dp[i][j-1])+1
return dp[m][n]
[0,i),[0,j] 匹配需要多少op