72. Edit Distance

72. Edit Distance

class Solution:

    def minDistance(self, word1: str, word2: str) -> int:
        m=len(word1)
        n=len(word2)

        dp=[[0 for j in range(n+1)] for i in range(m+1)]

        for i in range(1,m+1):
            dp[i][0]=i
        for j in range(1,n+1):
            dp[0][j]=j
        
        for i in range(1,m+1):
            for j in range(1,n+1):
                if word1[i-1]==word2[j-1]:
                    dp[i][j]=dp[i-1][j-1]
                else:
                    dp[i][j]=min(dp[i-1][j-1],dp[i-1][j],dp[i][j-1])+1
        return dp[m][n]

0,i),\[0,j\] 匹配需要多少op