作业2024/2/5 - 技术栈

第四章堆与拷贝构造函数

一、程序阅读题

1、给出下面程序输出结果。

#include <iostream.h>

class example

{int a;

public:

example(int b=5){a=b++;}

void print(){a=a+1;cout <<a<<"";}

void print()const

{cout<<a<<endl;}

};

void main()

{example x;

const example y(2);

x.print();

y.print();

}

6 2

2、运行程序，写出程序执行的结果。

#include<iostream.h>

class Location

{ public:

int X,Y;

void init(int initX,int initY);

int GetX();

int GetY();

};

void Location::init (int initX,int initY)

{X=initX;

Y=initY;

}

int Location::GetX()

{return X;

}

int Location::GetY()

{return Y;

}

void display(Location& rL)

{cout<<rL.GetX()<<" "<<rL.GetY()<<＼n;

}

void main()

{

Location A［5］={{5,5},{3,3},{1,1},{2,2},{4,4}};

Location *rA=A;

A［3］.init(7,3);

rA->init(7,8);

for (int i=0;i<5;i++)

display(*(rA++));

}

7 8

3 3

1 1

7 3

4 4

3. 给出下面程序输出结果。

#include <iostream.h>

int a[8］={1,2,3,4,5,6,7};

void fun(int *pa,int n);

void main()

{int m=8;

fun(a,m);

cout<<a［7］<<endl;

}

void fun(int *pa,int n)

{for (int i=0;i<n-1;i++)

*(pa+7)+=*(pa+i);

}

4. 给出下面程序输出结果。

#include <iostream.h>

class A

{

int *a;

public:

A(int x=0):a(new int(x)){}

~A() {delete a;}

int getA() {return *a;}

void setA(int x) {*a=x;}

};

void main()

{

A x1,x2(3);

A *p=&x2;

(*p).setA(x2.getA()+5);

x1.setA(10+x1.getA());

cout<<x1.getA()<<""<<x2.getA()<<endl;

}

10 8

阅读下面的程序，写出运行结果：

写出下面程序的运行结果，请用增加拷贝构造函数的方法避免存在的问题。

|-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| #include < iostream> using namespace std; class Vector { public: Vector (int s = 100); int& Elem(int ndx); void Display(); void Set (); ~Vector (); protected: int size; int* buffer; } Vector::Vector (int s) { buffer = new int $size = s$ ; for(int i = O; i<size; i + + ) buffer $i$ = i* i; } int& Vector:: Elem(int ndx) { if(ndx< 0 || ndx> = size) { cout << "error in index" <<endl; exit (1); } return buffer $ndx$ ; } void Vector::Display () { for(int j =0; j< size; j ++) cout << buffer $j$ <<endl; } void Vector:: Set () { for(int j =0; j<size; j++) buffer $j$ = j + 1; } Vector:: ~ Vector() { delete \[\] buffer; } int main() { Vector a(10); Vector b(a); a. Set (); b. Display (); return 0; } 加的构造函数 #include <iostream> using namespace std; class Vector { public: Vector(int s = 100); Vector(const Vector& other); // 拷贝构造函数 int& Elem(int ndx); void Display(); void Set(); ~Vector(); protected: int size; int* buffer; }; Vector::Vector(int s) { buffer = new int $size = s$ ; for (int i = 0; i < size; i++) buffer $i$ = i * i; } Vector::Vector(const Vector& other) { size = other.size; buffer = new int $size$ ; for (int i = 0; i < size; i++) buffer $i$ = other.buffer $i$ ; } int& Vector::Elem(int ndx) { if (ndx < 0 || ndx >= size) { cout << "error in index" << endl; exit(1); } return buffer $ndx$ ; } void Vector::Display() { for (int j = 0; j < size; j++) cout << buffer $j$ << endl; } void Vector::Set() { for (int j = 0; j < size; j++) buffer $j$ = j + 1; } Vector::~Vector() { delete\[\] buffer; } int main() { Vector a(10); Vector b(a); a.Set(); b.Display(); return 0; } |

7.读下面的程序与运行结果，添上一个拷贝构造函数来完善整个程序。

运行结果为：

frisky's age:5

Setting frisky to 6...

Creating boots from frisky

frisky's age:6

boots' age:6

Setting frisky to 7...

frisky's age:7

boots' age:6

添加

CAT::CAT(const CAT& other) {

itsAge = new int;

*itsAge = *other.itsAge;

}

CAT::~CAT() {

delete itsAge;

itsAge = 0;

}