Leetcode 740. Delete and Earn

Problem

You are given an integer array nums. You want to maximize the number of points you get by performing the following operation any number of times:

  • Pick any nums[i] and delete it to earn nums[i] points. Afterwards, you must delete every element equal to nums[i] - 1 and every element equal to nums[i] + 1.

Return the maximum number of points you can earn by applying the above operation some number of times.

Algorithm

Dynamics Programming (DP). F(n) = max(F(n-1), F(n-2)) {if nums[n] exists} else F(n) = F(n-1).

Code

python3 复制代码
class Solution:
    def deleteAndEarn(self, nums: List[int]) -> int:
        max_value = 0
        for num in nums:
            if max_value < num:
                max_value = num

        flag = [0] * (max_value + 1)
        for num in nums:
            flag[num] += 1
        
        ans = [0] * (max_value + 1)
        ans[1] = flag[1]
        for i in range(2, max_value+1):
            ans[i] = ans[i-1]
            if i > 1 and flag[i] and ans[i] < ans[i-2] + i * flag[i]:
                ans[i] = ans[i-2] + i * flag[i]
        
        return max(ans[max_value], ans[max_value-1])
相关推荐
z200509306 小时前
每日简单算法题——————跟着卡尔
算法
️是787 小时前
信息奥赛一本通—编程启蒙(3395:练68.3 车牌问题)
数据结构·c++·算法
Liangwei Lin8 小时前
LeetCode 118. 杨辉三角
算法·leetcode·职场和发展
计算机安禾8 小时前
【c++面向对象编程】第24篇:类型转换运算符:自定义隐式转换与explicit
java·c++·算法
鼠鼠我(‘-ωก̀ )好困8 小时前
leetGPU
算法
我星期八休息8 小时前
Linux系统编程—基础IO
linux·运维·服务器·c语言·c++·人工智能·算法
池塘的蜗牛8 小时前
A Low-Complexity Method for FFT-based OFDM Sensing
算法
故事和你919 小时前
洛谷-【图论2-1】树5
开发语言·数据结构·c++·算法·动态规划·图论
咖啡里的茶i9 小时前
视觉显著目标的自适应分割与动态网格生成算法研究
人工智能·算法·目标跟踪
paeamecium9 小时前
【PAT甲级真题】- String Subtraction (20)
数据结构·c++·算法·pat考试·pat