


1.纯暴力白嫖分
            
            
              java
              
              
            
          
          import java.util.*;
public class Main {
     public static void main (String []args) {
    	 Scanner a = new Scanner(System.in);
    	 int x1,x2,x3,x4,y1,y2,y3,y4;
    	 x1 =a.nextInt(); 
    	 y1 =a.nextInt();
    	 x2 =a.nextInt();
    	 y2 =a.nextInt();
    	 x3 =a.nextInt();
    	 y3 =a.nextInt();
    	 x4 =a.nextInt();
    	 y4 =a.nextInt();
    	 int area1 = (x2-x1)*(y2-y1);
    	 int area2 = (x4-x3)*(y4-y3);
    	 System.out.println(area1+area2);
     }
}
        2.穷举(我发现情况有点多穷举不完大概有个至少10种我得拿张草稿纸验算一下)
            
            
              java
              
              
            
          
          import java.util.*;
public class Main {
     public static void main (String []args) {
    	 Scanner a = new Scanner(System.in);
    	 long x1,x2,x3,x4,y1,y2,y3,y4;
    	 long area1,area2,n;
    	 long area3;//重合部分
    	 x1 =a.nextLong(); 
    	 y1 =a.nextLong();
    	 x2 =a.nextLong();
    	 y2 =a.nextLong();
    	 x3 =a.nextLong();
    	 y3 =a.nextLong();
    	 x4 =a.nextLong();
    	 y4 =a.nextLong();
    	 area1 = (x2-x1)*(y2-y1);
    	 area2 = (x4-x3)*(y4-y3);
    	 long a1 = Math.max(x1, x3);
    	 long a2 = Math.min(x2, x4);
    	 long b1 = Math.max(y1, y3);
    	 long b2 = Math.min(y2, y4);
    	 long n1 = area1+area2-(a2-a1)*(b2-b1);
//    	 //两个矩形不重合且不包含
//    	 if(x3>x2&&y3>y2) {
//    		 n = area1+area2;
//    	 }
//    	 else if(x4<x1&&y4<y1){
//    		 n = area1+area2;
//    	 }
//    	 else if(x3<x2 && x3>x1 && x4>x2 && y3>y1 && y3<y2 && y4>y2) {
//    		 n = area1+area2-(x2-x3)*(y2-y3);
//    	 }
//    	 else if(x4<x2 && x4>x1 && x3<x1 && y4>y1 && y4<y2 && y3<y1) {
//    		 n = area1+area2-(x4-x1)*(y4-y1);
//    	 }
//    	 else if(x3<x2 && x3>x1 && x4>x2 && y3<y1 && y4<y2 && y4>y1) {
//    		 n = area1+area2-(x4-x1)*(y4-y1);
//    	 }
//    	 else if(x4<x2 && x4>x1 && x3<x1 && y4>y1 && y4<y2 && y3<y1) {
//    		 n = area1+area2-(x4-x1)*(y4-y1);
//    	 }
//    	 else {
//    		 if(area1>area2) {
//    			 n = area1;
//    		 }
//    		 else
//    			 n = area2;
//    	 }
    	 System.out.println(n1);
     }
}
        3.巧法
            
            
              java
              
              
            
          
          import java.util.*;
public class Main {
     public static void main (String []args) {
    	 Scanner a = new Scanner(System.in);
    	 long x1,x2,x3,x4,y1,y2,y3,y4;
    	 long area1,area2,n;
    	 long area3;//重合部分
    	 x1 =a.nextLong(); 
    	 y1 =a.nextLong();
    	 x2 =a.nextLong();
    	 y2 =a.nextLong();
    	 x3 =a.nextLong();
    	 y3 =a.nextLong();
    	 x4 =a.nextLong();
    	 y4 =a.nextLong();
    	 area1 = (x2-x1)*(y2-y1);
    	 area2 = (x4-x3)*(y4-y3);
    	 long a1 = Math.max(x1, x3);
    	 long a2 = Math.min(x2, x4);
    	 long b1 = Math.max(y1, y3);
    	 long b2 = Math.min(y2, y4);
    	 long n1 = area1+area2-(a2-a1)*(b2-b1);
    	 System.out.println(n1);
     }
}