数字当索引-力扣-一次遍历

请你判断一个 9 x 9 的数独是否有效。只需要根据以下规则 ,验证已经填入的数字是否有效即可。

  1. 数字 1-9 在每一行只能出现一次。
  2. 数字 1-9 在每一列只能出现一次。
  3. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)

注意:

  • 一个有效的数独(部分已被填充)不一定是可解的。
  • 只需要根据以上规则,验证已经填入的数字是否有效即可。
  • 空白格用 '.' 表示。

示例 1:

复制代码
输入:board = 
[["5","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
输出:true

示例 2:

复制代码
输入:board = 
[["8","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
输出:false
解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。

提示:

  • board.length == 9
  • board[i].length == 9
  • board[i][j] 是一位数字(1-9)或者 '.'
cpp 复制代码
class Solution {
public:
    bool isValidSudoku(vector<vector<char>>& board) {
           int row[9][9];
           int low[9][9];
           int m[3][3][9];
        memset(row,0,sizeof(row));
        memset(low,0,sizeof(low));
        memset(m,0,sizeof(m));
        for(int i=0;i<9;i++)
        for(int j=0;j<9;j++)
        {
            if(board[i][j]=='.')continue;
            int index=board[i][j]-'0'-1;
             row[i][index]++;
             low[j][index]++;
             m[i/3][j/3][index]++;
             if(row[i][index]>1||low[j][index]>1||m[i/3][j/3][index]>1) return false;
        }
        return true;
    }
};
相关推荐
MrZhangBaby11 分钟前
SQL-leetcode—3374. 首字母大写 II
linux·sql·leetcode
only-lucky21 分钟前
C++中的 Eigen库使用
开发语言·c++
CoovallyAIHub34 分钟前
标注成本骤降,DINOv3炸裂发布!冻结 backbone 即拿即用,性能对标SOTA
深度学习·算法·计算机视觉
BB学长35 分钟前
流固耦合|01流固耦合分类
人工智能·算法
汤永红1 小时前
week3-[分支嵌套]方阵
c++·算法·信睡奥赛
广州智造1 小时前
EPLAN教程:流体工程
开发语言·人工智能·python·算法·软件工程·软件构建
自信的小螺丝钉1 小时前
Leetcode 343. 整数拆分 动态规划
算法·leetcode·动态规划
Q741_1471 小时前
C++ 力扣 438.找到字符串中所有字母异位词 题解 优选算法 滑动窗口 每日一题
c++·算法·leetcode·双指针·滑动窗口
草莓熊Lotso1 小时前
【C语言强化训练16天】--从基础到进阶的蜕变之旅:Day8
c语言·开发语言·c++·刷题·强化训练
Fine姐2 小时前
数据挖掘3.6~3.10 支持向量机—— 核化SVM
算法·支持向量机·数据挖掘