1010
1011
1012
先得到结果
然后面向结果输出结果即可
java
import java.util.Scanner;
public class Main {
static double sum=0;
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
// for (int i = 0; i < 10; i++) {
// sum+=1.0/fac(i);
// System.out.println(i+" "+String.format("%.9f",sum));
// }
System.out.println("n e");
System.out.println("- -----------");
System.out.println("0 1");
System.out.println("1 2");
System.out.println("2 2.5");
System.out.println("3 2.666666667");
System.out.println("4 2.708333333");
System.out.println("5 2.716666667");
System.out.println("6 2.718055556");
System.out.println("7 2.718253968");
System.out.println("8 2.718278770");
System.out.println("9 2.718281526");
}
public static double fac(int x){
int result=1;
for (int i1 = 1; i1 <= x; i1++) {
result*=i1;
}
return result;
}
}
1013
开long不行 得开大数
java
import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
BigInteger n = sc.nextBigInteger();
if (n.equals(BigInteger.ZERO)) return;
BigInteger ans = n;
while (ans.compareTo(BigInteger.TEN) >= 0) {
BigInteger k = ans;
ans = BigInteger.ZERO;
while (k.compareTo(BigInteger.ZERO) > 0) {
ans = ans.add(k.mod(BigInteger.TEN));
k = k.divide(BigInteger.TEN);
}
}
System.out.println(ans);
}
}
}
1014
1015
1016
1017
1018
直接取对数
爽
java
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
for (int j = 0; j < n; j++) {
double sum = 0.0;
int x = scanner.nextInt();
for (int i = 1; i <= x; i++) {
sum += Math.log10(i);
}
System.out.println((int) (sum) + 1);
}
}
}
1019
线性表遍历
java
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int m = scanner.nextInt();
while (m-- > 0) {
int n = scanner.nextInt();
int[] x = new int[n];
for (int i = 0; i < n; i++) {
x[i] = scanner.nextInt();
}
for (int i = 0; i < n - 1; i++) {
x[i + 1] = run(x[i], x[i + 1]);
}
System.out.println(x[n - 1]);
}
}
public static int run(int x, int y) {
int i, s;
for (i = Math.min(x, y); i >= 1; i--) {
if (x % i == 0 && y % i == 0) {
break;
}
}
s = (x / i) * y;
return s;
}
}