C. Mr. Perfectly Fine

time limit per test

2 seconds

memory limit per test

256 megabytes

Victor wants to become "Mr. Perfectly Fine". For that, he needs to acquire a certain set of skills. More precisely, he has 22 skills he needs to acquire.

Victor has nn books. Reading book ii takes him mimi minutes and will give him some (possibly none) of the required two skills, represented by a binary string of length 22.

What is the minimum amount of time required so that Victor acquires all of the two skills?

Input

The input consists of multiple test cases. The first line contains an integer tt (1≤t≤10001≤t≤1000) --- the number of test cases. The description of the test cases follows.

The first line of each test case contains an integer nn (1≤n≤2⋅1051≤n≤2⋅105) --- the number of books available.

Then nn lines follow. Line ii contains a positive integer mimi (1≤mi≤2⋅1051≤mi≤2⋅105) and a binary string of length 22, where si1=1si1=1 if reading book ii acquires Victor skill 11, and si1=0si1=0 otherwise, and si2=1si2=1 if reading book ii acquires Victor skill 22, and si2=0si2=0 otherwise.

It is guaranteed that the sum of nn over all test cases doesn't exceed 2⋅1052⋅105.

Output

For each test case, output a single integer denoting the minimum amount of minutes required for Victor to obtain both needed skills and −1−1 in case it's impossible to obtain the two skills after reading any amount of books.

Example

Input

Copy

复制代码

6

4

2 00

3 10

4 01

4 00

5

3 01

3 01

5 01

2 10

9 10

1

5 11

3

9 11

8 01

7 10

6

4 01

6 01

7 01

8 00

9 01

1 00

4

8 00

9 10

9 11

8 11

Output

Copy

复制代码
7
5
5
9
-1
8

Note

In the first test case, we can use books 22 and 33, with a total amount of minutes spent equal to 3+4=73+4=7.

In the second test case, we can use the books 11 and 44, with a total amount of minutes spent equal to 3+2=53+2=5.

In the third test case, we have only one option and that is reading book 11 for a total amount of minutes spent equal to 55.

解题说明:此题是一道模拟题,可以采用贪心算法,找出包含1和10的耗费最小时间组合或者是直接包含11的最小时间,两者进行比较即可。

cpp 复制代码
#include <stdio.h>

int main()
{
	int t = 0, n = 0, a = 0, s = 0;
	scanf("%d", &t);
	while (t--) 
	{
		scanf("%d", &n);
		int min_1 = 200005, min_2 = 200005, min_3 = 2000005;
		for (int i = 0; i < n; i++)
		{
			scanf("%d%d", &a, &s);
			if (1 == s && min_1 > a)
			{
				min_1 = a;
			}
			else if (10 == s && min_2 > a)
			{
				min_2 = a;
			}
			else if (11 == s && min_3 > a)
			{
				min_3 = a;
			}
		}
		if ((min_1 == 200005 || min_2 == 200005) && min_3 == 2000005)
		{
			printf("-1\n");
		}
		else if (min_1 + min_2 >= min_3)
		{
			printf("%d\n", min_3);
		}
		else
		{
			printf("%d\n", min_1 + min_2);
		}
	}
	return 0;
}
相关推荐
萧鼎1 小时前
Python并发编程库:Asyncio的异步编程实战
开发语言·数据库·python·异步
学地理的小胖砸1 小时前
【一些关于Python的信息和帮助】
开发语言·python
疯一样的码农1 小时前
Python 继承、多态、封装、抽象
开发语言·python
^velpro^1 小时前
数据库连接池的创建
java·开发语言·数据库
秋の花1 小时前
【JAVA基础】Java集合基础
java·开发语言·windows
小松学前端1 小时前
第六章 7.0 LinkList
java·开发语言·网络
可峰科技1 小时前
斗破QT编程入门系列之二:认识Qt:编写一个HelloWorld程序(四星斗师)
开发语言·qt
全栈开发圈1 小时前
新书速览|Java网络爬虫精解与实践
java·开发语言·爬虫
面试鸭1 小时前
离谱!买个人信息买到网安公司头上???
java·开发语言·职场和发展
小白学大数据1 小时前
JavaScript重定向对网络爬虫的影响及处理
开发语言·javascript·数据库·爬虫