C语言家教记录(七)
导语
本次授课的内容如下:字符串,结构体、联合体、枚举
辅助教材为 《C语言程序设计现代方法(第2版)》
字符串
字面量
双引号括起来的字符序列
c
"to be or not to be, is a question"
字面量需要用\来延续\
c
printf("When you come to a fork in the road, take it. \
--Yogi Berra");//必须顶格
字面量长度为n,则存储空间为n+1,字符串也可以为空,用单独的\0存储
c
char*s="abc";//不能修改内容
char ch;
ch = "abc"[1];
printf('\n');//非法,只能是字面量
变量
和整数一样,也可以用数组
说明一下数据的实际存储,探讨各情况下存储用的空间
c
char date1[8] = "June 14";
//等价于
char date1[8] = {'J', 'u', 'n', 'e', ' ', '1', '4', '\0'};
char date2[9] = "June 14";
char date3[7] = "June 14";
char date4[] = "June 14";
char *p;
char s[121];
p=str;
读写字符串
用printf、scanf控制输入输出
c
char str[] = "Are we having fun yet?";
printf("%s\n", str);
printf("%.6s\n", str);//思考一下会输出什么
scanf("%s",str);
用gets、puts控制输出
c
char s[121];
gets(s);//不知道数据长度有风险,fgets更好
puts(s);
逐个读入
c
int read_line(char str[], int n)
{
int ch, i = 0;
while ((ch = getchar()) != '\n')
if (i < n)
str[i++] = ch;
str[i] = '\0'; /* terminates string */
return i; /* number of characters stored */
}
示例程序
c
int count_spaces(const char s[])
{
int count = 0, i;
for (i = 0; s[i] != '\0'; i++)
if (s[i] == ' ')
count++;
return count;
}
操作函数
strcpy,strlen,strcat,strcmp
c
strcpy(str2, "abcd");
strcpy(str1, str2);
strcpy(str1, strcpy(str2, "abcd"));
int len;
len = strlen("abc"); /* len is now 3 */
len = strlen(""); /* len is now 0 */
strcpy(strl, "abc");
len = strlen(strl);
strcpy(str1, "abc");
strcat(str1, "def"); /* str1 now contains "abcdef" */
strcpy(str1, "abc");
strcpy(str2, "def");
strcat(str1, str2);
int strcmp(const char *s1, const char *s2);
if (strcmp(str1, str2) < 0)
惯用法
示例程序
c
size_t strlen(const char *s)
{
const char *p = s;
while (*s)
s++;
return s - p;
}
{
char *p = s1;
while (*p)
p++;
while (*p++ = *s2++)
;
return s1;
}
数组
探讨存储方式区别
c
char planets[][8] = {"Mercury", "Venus", "Earth",
"Mars", "Jupiter", "Saturn",
"Uranus", "Neptune", "Pluto"};
char *planets[] = {"Mercury", "Venus", "Earth",
"Mars", "Jupiter", "Saturn",
"Uranus", "Neptune", "Pluto"};
示例程序
c
#include <string.h>
#define NUM_PLANETS 9
int main(int argc, char *argv[])
{
char *planets[] = {"Mercury", "Venus", "Earth",
"Mars", "Jupiter", "Saturn",
"Uranus", "Neptune", "Pluto"};
int i, j;
for (i = 1; i < argc; i++) {
for (j = 0; j < NUM_PLANETS; j++)
if (strcmp(argv[i], planets[j]) == 0) {
printf("%s is planet %d\n", argv[i], j + 1);
break;
}
if (j == NUM_PLANETS)
printf("%s is not a planet\n", argv[i]);
}
return 0;
}
结构
c
struct {
int number;
char name[NAME_LEN+1];
int on_hand;
} part1, part2;
//介绍存储实现,视为一整个变量,可以认为生成了一个新的类型
struct{
char stu_name[10];
int id;
int grade;
}student;
struct {
int number;
char name[NAME_LEN+1];
int on_hand;
} part1 = {528, "Disk drive", 10},
part2 = {914, "Printer cable", 5};
//初始化,但是不推荐这么用;
//通过.运算符进行访问,或者用->
printf("Part number: %d\n", part1.number);
printf("Part name: %s\n", part1.name);
printf("Quantity on hand: %d\n", part1.on_hand);
Part1.number = 258; /* changes part1's part number */
Part1.on_hand++;
scanf("%d", &part1.on_hand);
part2 = part1;
struct { int a[10]; } a1, a2;
a1 = a2;
命名
c
struct part {
int number;
char name[NAME_LEN+1];
int on_hand;
};//一个新的类型
struct part part1, part2;//不能直接用part
struct part {
int number;
char name[NAME_LEN+1];
int on_hand;
} part1, part2;
typedef struct {
int number;
char name[NAME_LEN+1];
int on_hand;
} Part;//这之后可以用Part直接命名
示例程序
c
struct part build_part(int number, const char * name, int on_hand)
{
struct part p;
p.number = number;
strcpy (p.name, name);
p.on_hand = on_hand;
return p;
}
part1 = build_part(528, "Disk drive", 10);
其余部分见书
联合
解释一下存储实现
c
union {
int i;
double d;
} u;
union {
int i;
double d;
} u = {0};
示例程序
c
#define INT_KIND 0
#define DOUBLE_KIND 1
typedef struct {
int kind; /* tag field */
union{
int i;
double d;
} u;
} Number;
n.kind = INT_KIND;
n.u.i = 82;
void print_number(Number n)
{
if (n.kind == INT_KIND)
printf("%d", n.u.i);
else
printf("%g", n.u.d);
}
枚举
c
#define SUIT int
#define CLUBS 0
#define DIAMONDS 1
#define HEARTS 2
#define SPADES 3
enum {CLUBS, DIAMONDS, HEARTS, SPADES} s1, s2;
//等价于
enum suit {CLUBS, DIAMONDS, HEARTS, SPADES};
enum suit s1, s2;
//等价于
typedef enum {CLUBS, DIAMONDS, HEARTS, SPADES} Suit;
Suit s1, s2;
//c89中的bool
typedef enum {FALSE, TRUE} Bool;
enum suit {CLUBS = 1, DIAMONDS = 2, HEARTS = 3, SPADES = 4};
typedef struct {
enum {INT_KIND, DOUBLE_KIND} kind;
union {
int i;
double d;
} u;
} Number;
总结与复习
本次授课讲述第13章和第16章内容,关键点:字符串和新类型