算法训练营|图论第二天 99.岛屿数量 100.岛屿的最大面积

题目:99.岛屿数量

题目链接:

99. 岛屿数量 (kamacoder.com)

代码:

深度优先搜索:

cpp 复制代码
#include<bits/stdc++.h>
using namespace std;
int dir[4][2] = { 0,1,1,0,-1,0,0,-1 };
void dfs(vector<vector<int>>& grid, vector<vector<bool>>& visited, int x, int y) {
	for (int i = 0; i < 4; i++) {
		int nextx = x + dir[i][0];
		int nexty = y + dir[i][1];
		if (nextx < 0 || nexty < 0 || nextx >= grid.size() || nexty >= grid[0].size()) continue;
		if (grid[nextx][nexty] == 1 && !visited[nextx][nexty]) {
			visited[nextx][nexty] = true;
			dfs(grid, visited, nextx, nexty);
		}
	}
}
int main() {
	int n, m;
	cin >> n >> m;
	vector<vector<int>>grid(n, vector<int>(m, 0));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			cin >> grid[i][j];
		}
	}
	int result = 0;
	vector<vector<bool>>visited(n, vector<bool>(m, false));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			if (grid[i][j] == 1 && visited[i][j] == false) {
				dfs(grid, visited, i, j);
				result++;
			}
		}
	}
	cout << result << endl;
}

广度优先搜索:

cpp 复制代码
#include<bits/stdc++.h>
using namespace std;
int dir[4][2] = { 0,1,1,0,-1,0,0,-1 };
void bfs(vector<vector<int>>& grid, vector<vector<bool>>& visited, int x, int y) {
	queue<pair<int, int>>que;
	que.push({ x,y });
	while (!que.empty()) {
		pair<int, int> cur = que.front();
		que.pop();
		int curx = cur.first;
		int cury = cur.second;
		for (int i = 0; i < 4; i++) {
			int nextx = curx + dir[i][0];
			int nexty = cury + dir[i][1];
			if (nextx < 0 || nexty < 0 || nextx >= grid.size() || nexty >= grid[0].size()) continue;
			if (grid[nextx][nexty] && !visited[nextx][nexty]) {
				que.push({ nextx,nexty });
				visited[nextx][nexty] = true;
				bfs(grid, visited, nextx, nexty);
			}
		}
	}
}
int main() {
	int n, m;
	cin >> n >> m;
	vector<vector<int>>grid(n, vector<int>(m, 0));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			cin >> grid[i][j];
		}
	}
	int result = 0;
	vector<vector<bool>>visited(n, vector<bool>(m, false));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			if (grid[i][j] == 1 && !visited[i][j]) {
				result++;
				bfs(grid, visited, i, j);
			}
		}
	}
	cout << result << endl;
}

题目:100.岛屿的最大面积

题目链接:

100. 岛屿的最大面积 (kamacoder.com)

代码:

广搜:

cpp 复制代码
#include<bits/stdc++.h>
using namespace std;
int ans;
int dir[4][2] = { 0,1,1,0,-1,0,0,-1 };
void bfs(vector<vector<int>>& grid, vector<vector<bool>>& visited, int x, int y) {
	queue<pair<int, int>>que;
	que.push({ x,y });
	ans++;
	visited[x][y] = true;
	while (!que.empty()) {
		pair<int, int>cur = que.front();
		que.pop();
		int curx = cur.first;
		int cury = cur.second;
		for (int i = 0; i < 4; i++) {
			int nextx = curx + dir[i][0];
			int nexty = cury + dir[i][1];
			if (nextx < 0 || nexty < 0 || nextx >= grid.size() || nexty >= grid[0].size()) continue;
			if (grid[nextx][nexty] == 1 && !visited[nextx][nexty]) {
				visited[nextx][nexty] = true;
				que.push({ nextx,nexty });
				ans++;
			}
		}
	}
}
int main() {
	int n, m;
	cin >> n >> m;
	vector<vector<int>>grid(n, vector<int>(m, 0));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			cin >> grid[i][j];
		}
	}
	int result = 0;
	vector<vector<bool>>visited(n, vector<bool>(m, false));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			if (!visited[i][j] && grid[i][j]) {
				ans = 0;
				bfs(grid, visited, i, j);
				result = max(result, ans);
			}
		}
	}
	cout << result << endl;
}

深搜:

cpp 复制代码
#include<bits/stdc++.h>
using namespace std;
int ans;
int dir[4][2] = { 0,1,1,0,-1,0,0,-1 };
void dfs(vector<vector<int>>& grid, vector<vector<bool>>& visited, int x, int y) {
	if (grid[x][y] == 0 || visited[x][y]) return;
	visited[x][y] = true;
	ans++;
	for (int i = 0; i < 4; i++) {
		int nextx = x + dir[i][0];
		int nexty = y + dir[i][1];
		if (nextx < 0 || nexty < 0 || nextx >= grid.size() || nexty >= grid[0].size()) continue;
		dfs(grid, visited, nextx, nexty);
	}
}
int main() {
	int n, m;
	cin >> n >> m;
	vector<vector<int>>grid(n, vector<int>(m, 0));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			cin >> grid[i][j];
		}
	}
	int result = 0;
	vector<vector<bool>>visited(n, vector<bool>(m, false));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			if (!visited[i][j] && grid[i][j]) {
				ans = 0;
				dfs(grid, visited, i, j);
				result = max(result, ans);
			}
		}
	}
	cout << result << endl;
}

深搜思路2:

cpp 复制代码
#include<bits/stdc++.h>
using namespace std;
int ans;
int dir[4][2] = { 0,1,1,0,-1,0,0,-1 };
void dfs(vector<vector<int>>& grid, vector<vector<bool>>& visited, int x, int y) {
	for (int i = 0; i < 4; i++) {
		int nextx = x + dir[i][0];
		int nexty = y + dir[i][1];
		if (nextx < 0 || nexty < 0 || nextx >= grid.size() || nexty >= grid[0].size()) continue;
		if (!visited[nextx][nexty] && grid[nextx][nexty]) {
			visited[nextx][nexty] = true;
			ans++;
			dfs(grid, visited, nextx, nexty);
		}
	}
}
int main() {
	int n, m;
	cin >> n >> m;
	vector<vector<int>>grid(n, vector<int>(m, 0));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			cin >> grid[i][j];
		}
	}
	int result = 0;
	vector<vector<bool>>visited(n, vector<bool>(m, false));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			if (!visited[i][j] && grid[i][j]) {
				ans = 0;
				dfs(grid, visited, i, j);
				result = max(result, ans);
			}
		}
	}
	cout << result << endl;
}
相关推荐
geats人山人海1 小时前
数据结构第六章c语言 树的存储下二叉树的概念和存储
c语言·数据结构·算法
漂流瓶jz2 小时前
UVA-12627 奇怪的气球膨胀 题解答案代码 算法竞赛入门经典第二版
算法·图论·递归·aoapc·算法竞赛入门经典·uva·12627
jarvisuni2 小时前
DeepSeekFlash前端依旧拉垮,而且变慢了很多!
前端·javascript·算法
kobesdu2 小时前
流形上的优化:SO(3)与SE(3)的广义加减法在FAST-LIO中如何简化状态估计
人工智能·算法·fastlio
白狐_7982 小时前
408 数据结构算法题 01:线性表暴力求解保分指南
java·数据结构·算法
乐观勇敢坚强的老彭2 小时前
C++信奥:开关门、开关灯问题
开发语言·c++·算法
冻柠檬飞冰走茶2 小时前
PTA基础编程题目集 7-31 字符串循环左移(C语言实现)
c语言·开发语言·数据结构·算法
Hi李耶3 小时前
【LeetCode】4-寻找两个正序数组的中位数
算法·leetcode·职场和发展
图灵机z3 小时前
【算法提高课】AcWing 1027. 方格取数 长期攻克提高课-day3(3/219)
算法
hans汉斯3 小时前
计算机科学与应用|改进MeanShift算法在智能监控视频中的应用研究
图像处理·人工智能·功能测试·深度学习·算法·音视频