第4章
- 输出三个整数中的最大值
代码如下
c
#include <stdio.h>
int main()
{
int a, b, c;
int temp, max;
printf("a = ");
scanf("%d", &a);
printf("b = ");
scanf("%d", &b);
printf("c = ");
scanf("%d", &c);
temp = a > b ? a : b;
max = temp > c ? temp : c;
printf("max = %d\n", max);
return 0;
}- 大赛
代码如下
c
#include <stdio.h>
#include <math.h>
#define MAX 1000
int main()
{
int num, sqrt_num;
printf("num = ");
scanf("%d", &num);
while (num > MAX || num < 0)
{
printf("error, input again: \n");
scanf("%d", &num);
}
sqrt_num = sqrt(num);
printf("sqrt_num = %d\n", sqrt_num);
return 0;
}- 程序描述分段函数
代码如下
c
#include <stdio.h>
int main()
{
int x, y;
printf("x = ");
scanf("%d", &x);
if(x < 1)
{
y = x;
printf_s("x = %3d, y = %3d\n", x, y);
}
else if (x < 10)
{
y = 2 * x - 1;
printf_s("x = %3d, y = %3d\n", x, y);
}
else
{
y = 3 * x - 11;
printf_s("x = %3d, y = %3d\n", x, y);
}
return 0;
}- 对比两个程序
程序代码如下
c
/* 代码1 */
#include <stdio.h>
int main()
{
int x, y;
printf_s("x = ");
scanf("%d", &x);
y = -1;
if(x != 0)
{
if(x > 0)
{
y = 1;
}
}
else
{
y = 0;
}
printf_s("y = %d\n", y);
return 0;
}
/* 代码2 */
int main()
{
int x, y;
printf_s("x = ");
scanf("%d", &x);
y = 0;
if(x >= 0)
{
if(x > 0)
{
y = 1;
}
}
else
{
y = -1;
}
printf_s("y = %d\n", y);
return 0;
}程序1不满足题目要求，输入x<0时，输出y=0；程序2不满足题目要求，输入x<0时，输出y=0。
- 对成绩进行分级
代码如下
c
#include <stdio.h>
int main()
{
float score;
char grade;
printf("score = ");
scanf("%f", &score);
while (score < 0 || score > 100)
{
printf("error, input again: \n");
scanf("%f", &score);
}
switch((int)(score / 10))
{
case 10:
case 9:
grade = 'A';
break;
case 8:
grade = 'B';
break;
case 7:
grade = 'C';
break;
case 6:
grade = 'D';
break;
default:
grade = 'E';
break;
}
printf("grade = %c\n", grade);
return 0;
}- 判断数据
代码如下
c
int main()
{
int num, num_place;
int num_1, num_2, num_3, num_4, num_5;
printf_s("num = ");
scanf("%d", &num);
if(num > 9999)
{
num_place = 5;
}
else if(num > 999)
{
num_place = 4;
}
else if(num > 99)
{
num_place = 3;
}
else if(num > 9)
{
num_place = 2;
}
else
{
num_place = 1;
}
num_1 = num % 10;
num_2 = num % 100 / 10;
num_3 = num % 1000 / 100;
num_4 = num % 10000 / 1000;
num_5 = num / 10000;
printf("num_1 = %d\n", num_1);
printf("num_2 = %d\n", num_2);
printf("num_3 = %d\n", num_3);
printf("num_4 = %d\n", num_4);
printf("num_5 = %d\n", num_5);
printf("num_place = %d\n", num_place);
switch(num_place)
{
case 5:
printf("%d, %d, %d, %d, %d\n", num_5, num_4, num_3, num_2, num_1);
printf_s("\n reverse order: ");
printf("%d, %d, %d, %d, %d\n", num_1, num_2, num_3, num_4, num_5);
break;
case 4:
printf("%d, %d, %d, %d\n", num_4, num_3, num_2, num_1);
printf_s("\n reverse order: ");
printf("%d, %d, %d, %d\n", num_1, num_2, num_3, num_4);
break;
case 3:
printf("%d, %d, %d\n", num_3, num_2, num_1);
printf_s("\n reverse order: ");
printf("%d, %d, %d\n", num_1, num_2, num_3);
break;
case 2:
printf("%d, %d\n", num_2, num_1);
printf_s("\n reverse order: ");
printf("%d, %d\n", num_1, num_2);
break;
case 1:
printf("%d\n", num_1);
printf_s("\n reverse order: ");
printf("%d\n", num_1);
break;
default:
break;
}
return 0;
}- 企业发放奖金提成
代码如下
c
// if语句
double get_bonus_if(int profit)
{
double bonus, bon1, bon2, bon4, bon6, bon10;
bon1 = 100000 * 0.1;
bon2 = bon1 + 100000 * 0.075;
bon4 = bon2 + 100000 * 0.05;
bon6 = bon4 + 100000 * 0.03;
bon10 = bon6 + 400000 * 0.015;
if (profit <= 100000)
{
bonus = profit * 0.1;
}
else if (profit <= 200000)
{
bonus = bon1 + (profit - 100000) * 0.075;
}
else if (profit <= 400000)
{
bonus = bon2 + (profit - 200000) * 0.05;
}
else if (profit <= 600000)
{
bonus = bon4 + (profit - 400000) * 0.03;
}
else if (profit <= 1000000)
{
bonus = bon6 + (profit - 600000) * 0.015;
}
else
{
bonus = bon10 + (profit - 1000000) * 0.01;
}
return bonus;
}
// switch语句
double get_bonus_switch(int profit)
{
double bonus;
int branch = profit / 100000;
if (branch > 10)
branch = 10;
switch (branch)
{
case 0:
bonus = profit * 0.1;
break;
case 1:
bonus = 100000 * 0.1 + (profit - 100000) * 0.075;
break;
case 3:
bonus = 100000 * 0.1 + 100000 * 0.075 + (profit - 200000) * 0.05;
break;
case 5:
bonus = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + (profit - 400000) * 0.03;
break;
case 9:
bonus = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + 200000 * 0.03 + (profit - 600000) * 0.015;
break;
case 10:
bonus = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + 200000 * 0.03 + 400000 * 0.015 + (profit - 1000000) * 0.01;
break;
}
return bonus;
}
#include "funcs.h"
int main()
{
printf_s("the bonus is:%.2f\n", get_bonus_if(234000));
printf_s("the bonus is:%.2f\n", get_bonus_switch(234000));
return 0;
}- 四个整数排序
代码如下
c
// 采用依次比较法
void sort_fornums(int a, int b, int c, int d)
{
int temp;
if (a > b)
{
temp = a;
a = b;
b = temp;
}
if (c > d)
{
temp = c;
c = d;
d = temp;
}
if (a > c)
{
temp = a;
a = c;
c = temp;
}
if (b > d)
{
temp = b;
b = d;
d = temp;
}
if (b > c)
{
temp = b;
b = c;
c = temp;
}
printf("%d %d %d %d\n", a, b, c, d);
}- 求建筑高度
代码如下
c
// 根据该点到圆心的距离进行判断
int get_height(int x, int y)
{
int x1 = 2, y1 = 2, x2 = -2, y2 = 2, x3 = 2, y3 = -2, x4 = -2, y4 = -2;
float d1, d2, d3, d4;
d1 = (x - x1) * (x - x1) + (y - y1) * (y - y1);
d2 = (x - x2) * (x - x2) + (y - y2) * (y - y2);
d3 = (x - x3) * (x - x3) + (y - y3) * (y - y3);
d4 = (x - x4) * (x - x4) + (y - y4) * (y - y4);
if (d1 > 1 && d2 > 1 && d3 > 1 && d4 > 1)
{
return 0;
}
else
{
return 10;
}
}