代码随想录day16

搜索，双指针，采取两个指针遍历，采用前中右

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class Solution {
private:
int result = INT_MAX;
TreeNode* pre = NULL;
void traversal(TreeNode* cur) {
    if (cur == NULL) return;
    traversal(cur->left);   // 左
    if (pre != NULL){       // 中
        result = min(result, cur->val - pre->val);
    }
    pre = cur; // 记录前一个
    traversal(cur->right);  // 右
}
public:
    int getMinimumDifference(TreeNode* root) {
        traversal(root);
        return result;
    }
};

二叉树搜索树，统计众数

依旧是前序遍历，采用双指针的办法，但是要注意相同的情况，要放在前面

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/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    TreeNode* pre=NULL;
    vector<int> res;
    int count=0;
    int maxcount=INT_MIN;
    void traversal(TreeNode* cur){
        if(cur==NULL) return;
        traversal(cur->left);
    
       //第一个元素
        if(pre==NULL)   {count=1;} 
        else if(pre->val==cur->val) {count++;}
        else {count=1;} 
        if(count==maxcount){
            res.push_back(cur->val);
         }
        if(count>maxcount){
            maxcount=count;
            res.clear();
            res.push_back(cur->val);
        }
       
         
        pre=cur;

        traversal(cur->right);

    }
    vector<int> findMode(TreeNode* root) {
        traversal(root);
        return res;
        
    }
};

二叉树公共祖先，回溯算法，采用后序遍历

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/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public: 
  
    TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
        //回溯是后序遍历，左右中
        if(root==q||root==p||root==NULL) return root;

        TreeNode* left=lowestCommonAncestor(root->left,p,q);
        TreeNode* right=lowestCommonAncestor(root->right,p,q);

        if(left==NULL&&right!=NULL) return right;
        else if(left!=NULL&&right==NULL) return left;
        else if(left!=NULL&&right!=NULL) return root;
        else  {return NULL;}
        
    }
};