Leetcode 518. Coin Change II

Problem

You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money.

Return the number of combinations that make up that amount. If that amount of money cannot be made up by any combination of the coins, return 0.

You may assume that you have an infinite number of each kind of coin.

The answer is guaranteed to fit into a signed 32-bit integer.

Algorithm

Dynamic Programming (DP). Complete knapsack problem, forward to sum the ways.

Code

python3 复制代码
class Solution:
    def change(self, amount: int, coins: List[int]) -> int:
        dp = [0] * (amount + 1)
        dp[0] = 1
        for coin in coins:
            for v in range(coin, amount+1):
                dp[v] += dp[v - coin]
        
        return dp[amount]
相关推荐
码爸7 小时前
线性回归算法
算法·机器学习·线性回归
Coder-magician7 小时前
《代码随想录》刷题打卡day51:图论-part09(dijistra堆优化,Bellman_ford算法)
算法·图论
Nil2088 小时前
leetcode 763划分字母区间
算法·leetcode·职场和发展
不会就选b8 小时前
算法日常・每日刷题--<动态规划>20
算法·leetcode·动态规划
青少儿编程课堂9 小时前
迪杰斯特拉(Dijkstra)算法:单源最短路与赛场路线规划
c++·python·算法·bfs·信息学竞赛
不会就选b9 小时前
算法日常・每日刷题--<动态规划>19
算法·leetcode·职场和发展
没有钱的钱仔10 小时前
协方差矩阵含义
算法·机器学习·矩阵
垆边人似月.10 小时前
华为机试题 :和为 K 的子数组个数
算法·leetcode·华为
三*一10 小时前
优化修整算法
前端·javascript·算法