算法——图论——关键活动

原题

cpp 复制代码
#include <iostream>
#include <vector>
#include <queue>
#include <set>

using namespace std;

struct edge {
    int destination;
    int dist;

    edge(int destination_, int dist_) : destination(destination_), dist(dist_) {}
};

vector<edge> graph[100];
vector<edge> reGraph[100];
vector<int> inDo(100, 0);
vector<int> outDo(100, 0);
vector<int> lessTime(100, 0);
vector<int> moreTime(100, 0x3fffffff);

int main() {

    int n, m;
    cin >> n >> m;
    for (int i = 0; i < m; ++i) {
        int u, v, w;
        cin >> u >> v >> w;
        graph[u].emplace_back(v, w);
        reGraph[v].emplace_back(u, w);
        outDo[u]++;
        inDo[v]++;
    }
    queue<int> q;
    for (int i = 0; i < n; ++i) {
        if (inDo[i] == 0) {
            q.push(i);
            lessTime[i] = 0;
        }
    }

    while (!q.empty()) {
        int cur = q.front();
        q.pop();

        for (edge neighbor: graph[cur]) {
            inDo[neighbor.destination]--;
            lessTime[neighbor.destination] = max(lessTime[neighbor.destination], lessTime[cur] + neighbor.dist);
            if (inDo[neighbor.destination] == 0) {
                q.push(neighbor.destination);
            }
        }
    }

    int totalTime = 0;
    for (int i = 0; i < n; ++i) {
        if (inDo[i] != 0) {
            cout << "No" << endl;
            return 0;
        }
        totalTime = max(totalTime, lessTime[i]);
    }

    for (int i = 0; i < n; ++i) {
        if (outDo[i] == 0) {
            q.push(i);
            moreTime[i] = totalTime;
        }
    }


    while (!q.empty()) {
        int cur = q.front();
        q.pop();

        for (edge neighbor: reGraph[cur]) {
            outDo[neighbor.destination]--;
            moreTime[neighbor.destination] = min(moreTime[neighbor.destination], moreTime[cur] - neighbor.dist);
            if (outDo[neighbor.destination] == 0) {
                q.push(neighbor.destination);
            }
        }
    }

    set<pair<int, int>> s;
    for (int i = 0; i < n; ++i) {
    for (edge neighbor: graph[i]) {
        if (moreTime[neighbor.destination] - lessTime[i] - neighbor.dist == 0) {
            s.insert({i, neighbor.destination});
        }
    }
}

//    for (int i = 0; i < n; ++i) {
//        if (lessTime[i] == 0 && moreTime[i] == 0) {
//            q.push(i);
//        }
//    }

//    while (!q.empty()) {
//        auto cur = q.front();
//        q.pop();

//        for (auto neighbor: graph[cur]) {
//            if (lessTime[neighbor.destination] == moreTime[neighbor.destination]) {
//                s.insert({cur, neighbor.destination});
//            q.push(neighbor.destination);
//            }
//        }
//    }

    cout << "Yes" << endl;
    for (auto p: s) {
        cout << p.first << " " << p.second << endl;
    }
    return 0;
}
相关推荐
ZhengEnCi27 分钟前
同样的模型,为什么本地和云 API 差别那么大:量化精度、聊天模板与采样参数的三大元凶
人工智能·算法·llm
Flynn Liang1 小时前
RAG 答非所问/幻觉怎么破?Spring AI QuestionAnswerAdvisor 召回优化实战(TopK/重排/混合检索)
人工智能·算法·spring·rag·幻觉·springai
liminla!1 小时前
SQL 从入门到进阶:语法速查与实战练习(完整优化版)
数据库·sql·算法
维克兜率天2 小时前
【维克】指数调整:哪些股票会被“强制买入“?
人工智能·python·算法
罗西的思考3 小时前
【轻量化复刻大模型】线性注意力交互式演示
人工智能·算法·机器学习
神也畏惧菠萝3 小时前
Day08 Python流程控制从入门到上瘾:if/match/while/for四件套,从B站登录一路打到猜数字游戏
python·算法·数据存储·for·while·if·ifelse
揽星河..3 小时前
【C语言】分支和循环
c语言·c++·算法
Fuyo_11195 小时前
C++ AVL树保姆级详解:从平衡因子到四大旋转机制
java·c++·算法
jktantan5 小时前
每个节点 41 字节:把一棵百万节点树拆进 14 个 typed array
前端·javascript·vue.js·算法·typescript