题目描述:


代码:
用哈希表也可以解决,但真正考察的是用快慢指针法。
cpp
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
ListNode* fast = head;
ListNode* slow = head;
while(fast&&fast->next){
fast = fast->next->next;
slow = slow->next;
if(fast == slow)
return true;
}
return false;
}
};