给定一个二叉树的根节点 root ,返回 它的 中序 遍历 。
示例 1:

输入:root = 1,null,2,3
输出:1,3,2
示例 2:
输入:root = \[\]
输出:\[\]
示例 3:
输入:root = 1
输出:1
python
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution(object):
def inorderTraversal(self, root):
"""
:type root: Optional[TreeNode]
:rtype: List[int]
"""
res = []
def dfs(node):
if node is None:
return
dfs(node.left)
res.append(node.val)
dfs(node.right)
dfs(root)
return res