给定一个可包含重复数字的序列 nums ,按任意顺序 返回所有不重复的全排列。
示例 1:
输入:nums = [1,1,2]
输出:
\[1,1,2\], \[1,2,1\], \[2,1,1\]
示例 2:
输入:nums = [1,2,3]
输出:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
提示:
1 <= nums.length <= 8
-10 <= nums[i] <= 10
题出的跟白给一样,上一个写出来后稍加修改就行了
python
class Solution:
def __init__(self):
self.recode= {}
def merge(self,lis,target):
res = set()
for i in lis:
for j in range(len(i)+1):
new_i = i[::]
new_i.insert(j,target)
res.add(tuple(new_i))
return [list(i) for i in res]
def permuteUnique(self, nums: List[int]) -> List[List[int]]:
if len(nums) ==1:
return [nums]
res = []
for ind,v in enumerate(nums[1:],1):
key = tuple(nums[:ind])
tp = self.recode.get(key)
if not tp:
tp = self.permuteUnique(nums[:ind])
res = self.merge(tp,v)
self.recode[tuple(nums)] = res
return res
