LeetCode //C - 36. Valid Sudoku

36. Valid Sudoku

Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

  1. Each row must contain the digits 1-9 without repetition.
  2. Each column must contain the digits 1-9 without repetition.
  3. Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.

Note:

  • A Sudoku board (partially filled) could be valid but is not necessarily solvable.
  • Only the filled cells need to be validated according to the mentioned rules.

Example 1:

Input: board =

\["5","3",".",".","7",".",".",".","."

,"6",".",".","1","9","5",".",".","."

,".","9","8",".",".",".",".","6","."

,"8",".",".",".","6",".",".",".","3"

,"4",".",".","8",".","3",".",".","1"

,"7",".",".",".","2",".",".",".","6"

,".","6",".",".",".",".","2","8","."

,".",".",".","4","1","9",".",".","5"

,".",".",".",".","8",".",".","7","9"]
Output: true

Example 2:

Input: board =

\["8","3",".",".","7",".",".",".","."

,"6",".",".","1","9","5",".",".","."

,".","9","8",".",".",".",".","6","."

,"8",".",".",".","6",".",".",".","3"

,"4",".",".","8",".","3",".",".","1"

,"7",".",".",".","2",".",".",".","6"

,".","6",".",".",".",".","2","8","."

,".",".",".","4","1","9",".",".","5"

,".",".",".",".","8",".",".","7","9"]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.

Constraints:

  • board.length == 9
  • boardi.length == 9
  • boardij is a digit 1-9 or '.'.

From: LeetCode

Link: 36. Valid Sudoku


Solution:

Ideas:
  • Iterate through each cell in the board.
  • For each non-empty cell, check if its value violates the Sudoku rules.
  • The Sudoku rules require that each number (1-9) must not repeat in the same row, the same column, or the same 3x3 box.
  • We can use three 9x9 boolean matrices to track the existence of numbers in rows, columns, and boxes. The first matrix, rows, tracks numbers in each row, the second matrix, cols, tracks numbers in each column, and the third matrix, boxes, tracks numbers in each box.
  • If we find a number that has already existed in the current row, column, or box, return false. If we successfully go through the board without finding any duplicates, return true.
Code:
c 复制代码
bool isValidSudoku(char** board, int boardSize, int* boardColSize){
    bool rows[9][9] = {0};
    bool cols[9][9] = {0};
    bool boxes[9][9] = {0};

    for(int i = 0; i < 9; i++){
        for(int j = 0; j < 9; j++){
            if(board[i][j] != '.'){
                int num = board[i][j] - '1'; // subtract '1' to fit in 0-8 index
                int box_index = (i / 3) * 3 + j / 3; // map the box position to the box index
                
                // Check if this value has already been recorded in the current row, column, or box
                if(rows[i][num] || cols[j][num] || boxes[box_index][num]){
                    return false;
                }
                
                // Record the existence of the number in the current row, column, and box
                rows[i][num] = true;
                cols[j][num] = true;
                boxes[box_index][num] = true;
            }
        }
    }

    return true;
}
相关推荐
闻缺陷则喜何志丹9 分钟前
【栈 运算系统】P3719 [AHOI2017初中组] rexp|普及+
c++·算法··洛谷·运算系统
疯狂打码的少年32 分钟前
【数据库技术】多值依赖与第四范式(4NF)
数据库·笔记·算法
子文雨40 分钟前
基于 uC3845 与 ATtiny13 双芯片架构的 8.4V/2.5Ah 锂电池智能充电器设计
单片机·嵌入式硬件·算法
青山木1 小时前
Hot 100 --- 数组中的第K个最大元素
java·数据结构·算法·排序算法
玛卡巴卡ldf1 小时前
【AICoding】笔试提示词设计思路
java·算法·ai编程
明月_清风1 小时前
位图与布隆过滤器:海量数据下的"存在性判断"艺术
前端·后端·算法
Rnan-prince1 小时前
堆与TopK · 从零到通透 —— 9 节全系列复盘
python·算法
明月_清风1 小时前
Hash 表从入门到精通:Go 实战与工程细节
前端·后端·算法
nbsaas-boot2 小时前
多智能体系统的架构边界:任务编排、共享状态与故障隔离设计
人工智能·算法·动态规划
wuyk5552 小时前
12.归并排序:分治思想的稳定排序算法
开发语言·数据结构·算法·排序算法