LeetCode //C - 36. Valid Sudoku

36. Valid Sudoku

Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

  1. Each row must contain the digits 1-9 without repetition.
  2. Each column must contain the digits 1-9 without repetition.
  3. Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.

Note:

  • A Sudoku board (partially filled) could be valid but is not necessarily solvable.
  • Only the filled cells need to be validated according to the mentioned rules.

Example 1:

Input: board =

\["5","3",".",".","7",".",".",".","."

,"6",".",".","1","9","5",".",".","."

,".","9","8",".",".",".",".","6","."

,"8",".",".",".","6",".",".",".","3"

,"4",".",".","8",".","3",".",".","1"

,"7",".",".",".","2",".",".",".","6"

,".","6",".",".",".",".","2","8","."

,".",".",".","4","1","9",".",".","5"

,".",".",".",".","8",".",".","7","9"]
Output: true

Example 2:

Input: board =

\["8","3",".",".","7",".",".",".","."

,"6",".",".","1","9","5",".",".","."

,".","9","8",".",".",".",".","6","."

,"8",".",".",".","6",".",".",".","3"

,"4",".",".","8",".","3",".",".","1"

,"7",".",".",".","2",".",".",".","6"

,".","6",".",".",".",".","2","8","."

,".",".",".","4","1","9",".",".","5"

,".",".",".",".","8",".",".","7","9"]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.

Constraints:

  • board.length == 9
  • boardi.length == 9
  • boardij is a digit 1-9 or '.'.

From: LeetCode

Link: 36. Valid Sudoku


Solution:

Ideas:
  • Iterate through each cell in the board.
  • For each non-empty cell, check if its value violates the Sudoku rules.
  • The Sudoku rules require that each number (1-9) must not repeat in the same row, the same column, or the same 3x3 box.
  • We can use three 9x9 boolean matrices to track the existence of numbers in rows, columns, and boxes. The first matrix, rows, tracks numbers in each row, the second matrix, cols, tracks numbers in each column, and the third matrix, boxes, tracks numbers in each box.
  • If we find a number that has already existed in the current row, column, or box, return false. If we successfully go through the board without finding any duplicates, return true.
Code:
c 复制代码
bool isValidSudoku(char** board, int boardSize, int* boardColSize){
    bool rows[9][9] = {0};
    bool cols[9][9] = {0};
    bool boxes[9][9] = {0};

    for(int i = 0; i < 9; i++){
        for(int j = 0; j < 9; j++){
            if(board[i][j] != '.'){
                int num = board[i][j] - '1'; // subtract '1' to fit in 0-8 index
                int box_index = (i / 3) * 3 + j / 3; // map the box position to the box index
                
                // Check if this value has already been recorded in the current row, column, or box
                if(rows[i][num] || cols[j][num] || boxes[box_index][num]){
                    return false;
                }
                
                // Record the existence of the number in the current row, column, and box
                rows[i][num] = true;
                cols[j][num] = true;
                boxes[box_index][num] = true;
            }
        }
    }

    return true;
}
相关推荐
noipp8 小时前
推荐题目:洛谷 P6231 [JSOI2013] 公交系统
c语言·数据结构·c++·算法·游戏·洛谷·luogu
c238568 小时前
C/C++每日一练6
c语言·c++·算法
wdfk_prog8 小时前
嵌入式面试真题第 13 题:单硬件 Timer 下的高精度多路软件定时器架构设计
c语言·开发语言·面试·职场和发展·嵌入式
AI小码9 小时前
把动作「画」给视频世界模型,跨本体双向推演,李飞飞参与
大数据·人工智能·算法·ai·大模型·音视频·编程
时间的拾荒人9 小时前
MySQL C语言连接 - 从入门到实战
android·c语言·mysql
KaMeidebaby10 小时前
卡梅德生物技术快报|bli亲和力检测gst:告别批量跑胶:BLI实时酶切监测技术加速GST融合蛋白下游流程优化
前端·网络·数据库·人工智能·算法
alphaTao10 小时前
LeetCode 每日一题 2026/7/20-2026/7/26
算法·leetcode
圣保罗的大教堂11 小时前
leetcode 3514. 不同 XOR 三元组的数目 II 中等
leetcode
code_pgf11 小时前
C/C++ 中 `typedef` 关键字详解
c语言·c++
青山木14 小时前
Hot 100 ---腐烂的橘子
java·数据结构·后端·算法·leetcode·广度优先