LeetCode //C - 36. Valid Sudoku

36. Valid Sudoku

Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

  1. Each row must contain the digits 1-9 without repetition.
  2. Each column must contain the digits 1-9 without repetition.
  3. Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.

Note:

  • A Sudoku board (partially filled) could be valid but is not necessarily solvable.
  • Only the filled cells need to be validated according to the mentioned rules.

Example 1:

Input: board =

\["5","3",".",".","7",".",".",".","."

,"6",".",".","1","9","5",".",".","."

,".","9","8",".",".",".",".","6","."

,"8",".",".",".","6",".",".",".","3"

,"4",".",".","8",".","3",".",".","1"

,"7",".",".",".","2",".",".",".","6"

,".","6",".",".",".",".","2","8","."

,".",".",".","4","1","9",".",".","5"

,".",".",".",".","8",".",".","7","9"]
Output: true

Example 2:

Input: board =

\["8","3",".",".","7",".",".",".","."

,"6",".",".","1","9","5",".",".","."

,".","9","8",".",".",".",".","6","."

,"8",".",".",".","6",".",".",".","3"

,"4",".",".","8",".","3",".",".","1"

,"7",".",".",".","2",".",".",".","6"

,".","6",".",".",".",".","2","8","."

,".",".",".","4","1","9",".",".","5"

,".",".",".",".","8",".",".","7","9"]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.

Constraints:

  • board.length == 9
  • boardi.length == 9
  • boardij is a digit 1-9 or '.'.

From: LeetCode

Link: 36. Valid Sudoku


Solution:

Ideas:
  • Iterate through each cell in the board.
  • For each non-empty cell, check if its value violates the Sudoku rules.
  • The Sudoku rules require that each number (1-9) must not repeat in the same row, the same column, or the same 3x3 box.
  • We can use three 9x9 boolean matrices to track the existence of numbers in rows, columns, and boxes. The first matrix, rows, tracks numbers in each row, the second matrix, cols, tracks numbers in each column, and the third matrix, boxes, tracks numbers in each box.
  • If we find a number that has already existed in the current row, column, or box, return false. If we successfully go through the board without finding any duplicates, return true.
Code:
c 复制代码
bool isValidSudoku(char** board, int boardSize, int* boardColSize){
    bool rows[9][9] = {0};
    bool cols[9][9] = {0};
    bool boxes[9][9] = {0};

    for(int i = 0; i < 9; i++){
        for(int j = 0; j < 9; j++){
            if(board[i][j] != '.'){
                int num = board[i][j] - '1'; // subtract '1' to fit in 0-8 index
                int box_index = (i / 3) * 3 + j / 3; // map the box position to the box index
                
                // Check if this value has already been recorded in the current row, column, or box
                if(rows[i][num] || cols[j][num] || boxes[box_index][num]){
                    return false;
                }
                
                // Record the existence of the number in the current row, column, and box
                rows[i][num] = true;
                cols[j][num] = true;
                boxes[box_index][num] = true;
            }
        }
    }

    return true;
}
相关推荐
暴力求解5 分钟前
C++ ---继承(二)
开发语言·c++·算法
码林拾遗WJ29 分钟前
告警分级的自动化实测:模型判断 vs 人工拍板
人工智能·算法·自动化
Tisfy43 分钟前
LeetCode 0453.最小操作次数使数组元素相等:两次遍历(反向思维)
算法·leetcode·题解·遍历·反向思维
君万1 小时前
【LeetCode每日一题】回溯:46. 全排列 78. 子集 39. 组合总和
算法·leetcode·go
Keep_Trying_Go2 小时前
Consistent-Point半监督人群计数算法详解
人工智能·深度学习·算法·计算机视觉·人群计数
在所不辞兄2 小时前
【零基础学智能仿真-69】综合项目——材料参数驱动的仿真研究
人工智能·深度学习·神经网络·算法·机器学习·1024程序员节
Tisfy3 小时前
LeetCode 3665.统计镜子反射路径数目:三个动态规划数组
leetcode·动态规划·代理模式·题解
怕浪猫3 小时前
Super-agent 在各大模型厂商的应用情况
算法·面试·github
海绵宝宝转agent4 小时前
LeetCode100 二叉树个人题解
算法·leetcode·深度优先
octopus_c4 小时前
C++ 模板详解:函数模板、类模板、特化与分离编译
开发语言·c++·算法