LeetCode75——Day26

文章目录

一、题目

394. Decode String

Given an encoded string, return its decoded string.

The encoding rule is: kencoded_string, where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer.

You may assume that the input string is always valid; there are no extra white spaces, square brackets are well-formed, etc. Furthermore, you may assume that the original data does not contain any digits and that digits are only for those repeat numbers, k. For example, there will not be input like 3a or 24.

The test cases are generated so that the length of the output will never exceed 105.

Example 1:

Input: s = "3a2bc"

Output: "aaabcbc"

Example 2:

Input: s = "3a2\[c]"

Output: "accaccacc"

Example 3:

Input: s = "2abc3cdef"

Output: "abcabccdcdcdef"

Constraints:

1 <= s.length <= 30

s consists of lowercase English letters, digits, and square brackets '\[\]'.

s is guaranteed to be a valid input.

All the integers in s are in the range 1, 300.

二、题解

cpp 复制代码
class Solution {
public:
    string decodeString(string s) {
        string ans;
        stack<pair<int, int>> stk;
        int count = 0;
        for (auto x : s) {
            if (isdigit(x)) 
                count = 10 * count + (x - '0');
            else if (x == '[') {
                stk.push({count, ans.size()});
                count = 0;
            }
            else if (isalpha(x)) 
                ans += x;
            else if (x == ']') {
                int n = stk.top().first;
                string str = ans.substr(stk.top().second, ans.size() - stk.top().second);
                for (int i = 0; i < n - 1; i++) {
                    ans += str;
                }
                stk.pop();
            }
        }
        return ans;
    }
}; 
相关推荐
夏幻灵3 小时前
每日一题:LeetCode 3:无重复字符的最长子串——滑动窗口思路详解
算法·leetcode·职场和发展
CarIise3 小时前
Java实训阶段查漏补缺复习笔记2
java·linux·算法
无忧.芙桃3 小时前
C++ 并查集详解:原理、实现与应用
c语言·c++·算法·leetcode
蛋蛋的就会顺顺的3 小时前
hot100——二叉树
java·数据结构·算法·leetcode·力扣
Code_Solitude4 小时前
c语言:二分法的完整补充
c语言·开发语言·算法
一切皆是因缘际会4 小时前
掌控信息论:同源星际通信基础理论
人工智能·算法·ai
智者知已应修善业4 小时前
【51单片机只有一个8*8点阵数据如何滚动起来一片595+一组IO+花样】2022-1-15
c++·经验分享·笔记·单片机·蓝桥杯·硬件架构
水饺编程4 小时前
第1章,[Win32 章节]:Windows 简史
c语言·c++·visual studio
ShineWinsu5 小时前
对于Redis:事务的解析
数据库·redis·mysql·缓存·面试·事务·acid
List<String> error_P5 小时前
freertos数据结构--链表
数据结构·链表