LeetCode75——Day26

文章目录

一、题目

394. Decode String

Given an encoded string, return its decoded string.

The encoding rule is: kencoded_string, where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer.

You may assume that the input string is always valid; there are no extra white spaces, square brackets are well-formed, etc. Furthermore, you may assume that the original data does not contain any digits and that digits are only for those repeat numbers, k. For example, there will not be input like 3a or 24.

The test cases are generated so that the length of the output will never exceed 105.

Example 1:

Input: s = "3a2bc"

Output: "aaabcbc"

Example 2:

Input: s = "3a2\[c]"

Output: "accaccacc"

Example 3:

Input: s = "2abc3cdef"

Output: "abcabccdcdcdef"

Constraints:

1 <= s.length <= 30

s consists of lowercase English letters, digits, and square brackets '\[\]'.

s is guaranteed to be a valid input.

All the integers in s are in the range 1, 300.

二、题解

cpp 复制代码
class Solution {
public:
    string decodeString(string s) {
        string ans;
        stack<pair<int, int>> stk;
        int count = 0;
        for (auto x : s) {
            if (isdigit(x)) 
                count = 10 * count + (x - '0');
            else if (x == '[') {
                stk.push({count, ans.size()});
                count = 0;
            }
            else if (isalpha(x)) 
                ans += x;
            else if (x == ']') {
                int n = stk.top().first;
                string str = ans.substr(stk.top().second, ans.size() - stk.top().second);
                for (int i = 0; i < n - 1; i++) {
                    ans += str;
                }
                stk.pop();
            }
        }
        return ans;
    }
}; 
相关推荐
梓䈑4 小时前
【算法题攻略】BFS 解决FloodFill 算法、最短路问题、多源BFS 和 拓扑排序
c++·算法·宽度优先
Adios7946 小时前
设置交集大小至少为2
数据结构·算法·leetcode
程序喵大人9 小时前
【C++进阶】STL容器与迭代器 - 01 STL 容器先解决元素放在哪里
开发语言·c++·stl
触底反弹10 小时前
🚀 从 DOM0 级到 React 合成事件:前端事件监听的 20 年演进史
前端·react.js·面试
kyriewen10 小时前
我给前端项目的接口请求套了6层保护——才发现以前一直在裸奔
前端·javascript·面试
wdfk_prog10 小时前
嵌入式面试真题第 15 题:不可恢复异常后的通用崩溃快照、调用栈保存与离线分析架构
linux·开发语言·面试·架构
野生风长13 小时前
C++入门基础:从命名空间到引用与指针的全面解析
开发语言·c++
LayZhangStrive13 小时前
JUC相关的函数、注解、变量杂记
java·面试·多线程·juc
来一碗刘肉面13 小时前
栈的应用(表达式求值)
数据结构·算法