LeetCode75——Day26

文章目录

一、题目

394. Decode String

Given an encoded string, return its decoded string.

The encoding rule is: kencoded_string, where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer.

You may assume that the input string is always valid; there are no extra white spaces, square brackets are well-formed, etc. Furthermore, you may assume that the original data does not contain any digits and that digits are only for those repeat numbers, k. For example, there will not be input like 3a or 24.

The test cases are generated so that the length of the output will never exceed 105.

Example 1:

Input: s = "3a2bc"

Output: "aaabcbc"

Example 2:

Input: s = "3a2\[c]"

Output: "accaccacc"

Example 3:

Input: s = "2abc3cdef"

Output: "abcabccdcdcdef"

Constraints:

1 <= s.length <= 30

s consists of lowercase English letters, digits, and square brackets '\[\]'.

s is guaranteed to be a valid input.

All the integers in s are in the range 1, 300.

二、题解

cpp 复制代码
class Solution {
public:
    string decodeString(string s) {
        string ans;
        stack<pair<int, int>> stk;
        int count = 0;
        for (auto x : s) {
            if (isdigit(x)) 
                count = 10 * count + (x - '0');
            else if (x == '[') {
                stk.push({count, ans.size()});
                count = 0;
            }
            else if (isalpha(x)) 
                ans += x;
            else if (x == ']') {
                int n = stk.top().first;
                string str = ans.substr(stk.top().second, ans.size() - stk.top().second);
                for (int i = 0; i < n - 1; i++) {
                    ans += str;
                }
                stk.pop();
            }
        }
        return ans;
    }
}; 
相关推荐
Rain的Java大神之路9 小时前
国家数据集团校招、社招都开了:总部雄安,这些技术岗值得认真看看
java·后端·面试
一去不复返的通信er9 小时前
排序 + 双指针:力扣15三数之和
算法·leetcode
Moment9 小时前
为什么这么多 Agent Harness 都选择 TypeScript
前端·后端·面试
文丑颜不良啊9 小时前
LeetCode1901~1920题目解析
java·leetcode
落樱弥城10 小时前
Perf 逐步探查性能缺口并优化
c++·性能优化
Pniubi10 小时前
力扣3无重复字符的最长字串(滑动窗口)
算法·leetcode·职场和发展
坤坤子吖10 小时前
Linux网络编程:UDP进阶,从字典服务器到简单聊天室
linux·服务器·网络·c++·笔记·学习
On The Road :10 小时前
深入理解 JVM 垃圾回收:GC 是什么、如何判定垃圾、四大回收算法全解析
jvm·算法
Rabitebla10 小时前
【Linux学习笔记】进程篇(九):进程的创建与退出——fork、写时拷贝与退出码
linux·c++·笔记·学习
时间的拾荒人10 小时前
CMake 实战指南:从基础语法到静态库/动态库制作与链接
开发语言·c++·面试