leetcode刷题日志-146LRU缓存

思路：使用hashmap储存key，vaule，使用双向链表以快速查到尾结点（待逐出的节点），链表的题一定要在纸上画一下，不然连着连着就不知道连在哪里去了

class LRUCache {
    public class ListNode {
      int key;
      int value;
      ListNode next;
      ListNode pre;
      ListNode() {}
      ListNode(int key , int value) { this.key = key; this.value = value;}
      ListNode(int kye, int value, ListNode next) { this.key = key;this.value = value;this.next = next;}
      ListNode(int kye, int value, ListNode next,ListNode pre) { this.key = key;this.value = value;this.next = next;this.pre = pre;}
  }
    ListNode head;//头节点
    ListNode tail;//指向尾结点的前一个节点，方便逐出最久未使用关键字
    int capacity; //储存容量
    int cur_capacity;//储存当前容量
    Map<Integer,ListNode> map;//储存节点
    
    public LRUCache(int capacity) {
        this.head = new ListNode(0,0,null,null);
        this.capacity = capacity;
        this.cur_capacity = 0;
        this.map = new HashMap<>();
        this.tail = new ListNode(0,0,null,head);
        this.head.next = tail;
    }
    
    public int get(int key) {
        if(map.containsKey(key))  //最近使用到的key，将位置提前
        {
            if(map.get(key).next != null)
            {
                map.get(key).next.pre = map.get(key).pre;
                map.get(key).pre.next = map.get(key).next;
            }
            map.get(key).next = head.next;
            map.get(key).next.pre = map.get(key);
            map.get(key).pre = head;
            head.next = map.get(key);
            return map.get(key).value;
        }
        else
            return -1;
    }
    
    public void put(int key, int value) {
        if(map.containsKey(key)) //存在,将位置提前
        {
            map.get(key).value = value;
            if(map.get(key).next != null)
            {
                map.get(key).next.pre = map.get(key).pre;
                map.get(key).pre.next = map.get(key).next;
            }
            map.get(key).next = head.next;
            map.get(key).next.pre = map.get(key);
            map.get(key).pre = head;
            head.next = map.get(key);
        }
        else{//不存在
            if(this.cur_capacity < this.capacity) //容量足够，直接添加到头
            {
                ListNode temp = new ListNode();
                temp.key = key;
                temp.value = value;
                temp.next = head.next;
                if(temp.next != null)
                temp.next.pre = temp;
                temp.pre = head;
                head.next = temp;
                cur_capacity++;
                map.put(key,temp);
            }
            else//容量不够，移出尾结点，添加新节点到头
            {

                ListNode tail_pre = tail.pre;
                map.remove(tail_pre.key);
                tail.pre.pre.next = tail;
                tail.pre.next = null;
                tail.pre = tail.pre.pre;
                tail_pre.pre = null;
                ListNode temp = new ListNode();
                temp.key = key;
                temp.value = value;
                temp.next = head.next;
                temp.next.pre = temp;
                temp.pre = head;
                head.next = temp;
                map.put(key,temp);
            }
        }
    }
}

/**
 * Your LRUCache object will be instantiated and called as such:
 * LRUCache obj = new LRUCache(capacity);
 * int param_1 = obj.get(key);
 * obj.put(key,value);
 */