LeetCode354. Russian Doll Envelopes——动态规划

文章目录

• • 一、题目
  • 二、题解

一、题目

You are given a 2D array of integers envelopes where envelopesi = wi, hi represents the width and the height of an envelope.

One envelope can fit into another if and only if both the width and height of one envelope are greater than the other envelope's width and height.

Return the maximum number of envelopes you can Russian doll (i.e., put one inside the other).

Note: You cannot rotate an envelope.

Example 1:

Input: envelopes = \[5,4,6,4,6,7,2,3]

Output: 3

Explanation: The maximum number of envelopes you can Russian doll is 3 (2,3 => 5,4 => 6,7).

Example 2:

Input: envelopes = \[1,1,1,1,1,1]

Output: 1

Constraints:

1 <= envelopes.length <= 105

envelopesi.length == 2

1 <= wi, hi <= 105

二、题解

class Solution {
public:
    static bool cmp(vector<int>& e1,vector<int>& e2){
        return e1[0] < e2[0] || (e1[0] == e2[0] && e1[1] > e2[1]);
    }
    int maxEnvelopes(vector<vector<int>>& envelopes) {
        int n = envelopes.size();
        vector<int> ends(n,0);
        int len = 0;
        sort(envelopes.begin(),envelopes.end(),cmp);
        for(int i = 0;i < n;i++){
            int num = envelopes[i][1];
            int index = binarySearch(ends,len,num);
            if(index == -1) ends[len++] = num;
            else ends[index] = num;
        }
        return len;
    }
    int binarySearch(vector<int>& ends,int len,int num){
        int l = 0, r = len - 1,res = -1;
        while(l <= r){
            int mid = (l + r) / 2;
            if(ends[mid] >= num){
                res = mid;
                r = mid - 1;
            }
            else l = mid + 1;
        }
        return res;
    }
};