dp练习2

如何分析这个题目呢，要想着当前的最优解只和前面的最优解有关

class Solution {
public:
    int numSquares(int n) {
        vector<int> f(n + 1);
        for (int i = 1; i <= n; i++) {
            int minn = INT_MAX;
            for (int j = 1; j * j <= i; j++) {
                minn = min(minn, f[i - j * j]);
            }
            f[i] = minn + 1;
        }
        return f[n];
    }
};

class Solution {
public:
    int uniquePaths(int m, int n) {
        int dp[105][105];
        for (int i = 0; i <= m; i++) {
            dp[0][1] = 1;
            for (int i = 1; i <= m; i++) {
                for (int j = 1; j <= n; j++) {
                    dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
                }
            }
        }
        return dp[m][n];
    }
};