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easy
使用两个数组shuax,shuay分别记录为0的i和j下标
然后两个for循环分别对行,列刷一次就可以了,虽然这样很浪费内存并且复杂度有点高,但能过就行。
python
class Solution:
def setZeroes(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
m=len(matrix)
n=len(matrix[0])
shuax=[]
shuay=[]
for i in range(m):
for j in range(n):
if matrix[i][j]==0:
shuax.append(i)
shuay.append(j)
for i in range(m):
if i in shuax:
for j in range(n):
matrix[i][j]=0
for j in range(n):
if j in shuay:
for i in range(m):
matrix[i][j]=0
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