C语言 | Leetcode C语言题解之第328题奇偶链表

题目：

题解：

struct ListNode* oddEvenList(struct ListNode* head) {
    if (head == NULL) {
        return head;
    }
    struct ListNode* evenHead = head->next;
    struct ListNode* odd = head;
    struct ListNode* even = evenHead;
    while (even != NULL && even->next != NULL) {
        odd->next = even->next;
        odd = odd->next;
        even->next = odd->next;
        even = even->next;
    }
    odd->next = evenHead;
    return head;
}