122. 买卖股票的最佳时机 II - 力扣(LeetCode)
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python
class Solution:
def maxProfit(self, prices: List[int]) -> int:
max_profit = 0 # 初始化最大利润为0
for i in range(1, len(prices)):
if prices[i] > prices[i - 1]:
max_profit += prices[i] - prices[i - 1] # 累加利润
return max_profit