编写版本：vc++2022
1.求最大/小值
cpp
#include<stdio.h>
int main(){
int a[50],n;
int max, min;
printf("请输入您要输入几个数");
scanf_s("%d", &n);
printf("请输入您要比较的%d个数\n",n);
for (int i = 0; i<n; i++) {
scanf_s("%d", &a[i]);
}
max = min = a[0];
for (int i = 0; i < n; i++) {
if (a[i] > max) max = a[i];
if (a[i] < min) min = a[i];
}
printf("max=%d,min=%d", max, min);
return 0;
}2.求一个三位数abc，使a的阶乘+b的阶乘+c的阶乘=abc
cpp
#include<stdio.h>
//factorial 阶乘
int jiecheng(int n) {
int m=1;
while (n != 0) {
m *= n;
n--;
}
return m;
}
int main() {
int a, b, c;
for (int abc = 100; abc <= 999; abc++) {
a = abc / 100;
b = abc / 10 % 10;
c = abc % 10;
if (abc == jiecheng(a) + jiecheng(b) + jiecheng(c))
printf("%d\n", abc);
}
return 0;
}3.求2/1，3/2，5/3，8/5，13/8，21/13，的前20项和
cpp
#include<stdio.h>
int main() {
float sum = 2;
int i = 1, j = 2;
float k;
for (int num = 1; num < 20; num++) {
k = i + j;
i = j;
sum += k / i;
j = k;
}
printf("%0.2f", sum);
return 0;
}4.求阶乘
cpp
#include<stdio.h>
int main() {
int N;
int jiecheng=1;
scanf_s("%d", &N);
while (N != 0) {
jiecheng *= N;
N--;
}
printf("%d\n", jiecheng);
return 0;
}5.求10-1000之间所有数字之和为5的整数的个数
cpp
#include<stdio.h>
int main() {
int count = 0;
for (int i = 10; i <= 99; i++) {//两位数
if (i/10+i%10== 5)
count++;
}
for (int i = 100; i <= 999; i++) {//三位数
if ((i/100)+(i/10%10)+(i%10)== 5)
count++;
}
printf("%d\n", count);
return 0;
}6.输入字符串打印除小写，元音，字母之外的。用数组
cpp
#include<stdio.h>
int main() {
char a[50];
scanf_s("%s", a, 50);
for (int i = 0; a[i] != '\0'; i++)
if (a[i] != 'a' && a[i] != 'e' && a[i] != 'i' && a[i] != 'o' && a[i] != 'u')
printf("%c", a[i]);
return 0;
}scanf_s输入字符串时，需要添加长度防止溢出
7.计算输入的10个整数中的，偶数的和，偶数平均值（小数表示）
cpp
#include<stdio.h>
int main() {
int a[10];
int sum=0;
double avg;
for (int i = 0; i < 10; i++) {
scanf_s("%d", &a[i]);
if (a[i] % 2 == 0) sum += a[i];
}
avg = sum / 10.0;
printf("偶数的和%d,偶数的平均值%0.2f", sum, avg);
return 0;
}8.循环语句求a+aa+aaa+aaaa......n个a，n和a由键盘输入
cpp
#include<stdio.h>
#include<math.h>
int main() {
int a, n,m;
int sum = 0;
scanf_s("%d %d", &a, &n);
m = a;
for (int i = 1; i <= n; i++) {
sum += m;
m += a * pow(10, i);
}
printf("%d", sum);
return 0;
}9.1！+2！+3！+4！......
cpp
#include<stdio.h>
int main() {
int sum = 0, n,m=1;
scanf_s("%d", &n);
for (int i = 1; i <= n; i++) {
m *= i;
sum += m;
}
printf("%d", sum);
return 0;
}10.求sum=1-1/3+1/5-1/7+ +1/n（1/n<0.0001)
cpp
#include<stdio.h>
int main() {
float sum = 0;
int k=1;
for (int i = 1; (1.0 / i) >= 0.0001; i += 2) {
sum += (1.0 / i) * k;
k = -k;
}
printf("%0.2f", sum);
return 0;
}11.输入正数判断是否为素数
cpp
#include<stdio.h>
int main() {
int i,n;
scanf_s("%d", &n);
//素数：=质数，除了1和它本身之外不能被其他数整除。否则称为合数（1既不是质数也不是合数）
if (n == 1) printf("%d不是素数", n);
else if (n == 2) printf("%d是素数", n);
else {
for (i = 2; i < n; i++) {
if (n % i == 0) {
printf("%d不是素数", n);
break;
}
}
if(i>=n) printf("%d是素数", n);
}
return 0;
}12.编写一个计算器，可以计算+-*/
cpp
#include<stdio.h>
int main() {
float a, b;
char ch;
scanf_s("%f", &a);
ch = getchar();
scanf_s("%f", &b);
switch (ch) {
case '+':printf("=%0.2f", a + b); break;
case '-':printf("=%0.2f", a - b); break;
case '*':printf("=%0.2f", a * b); break;
case '/':printf("=%0.2f", a / b); break;
}
return 0;
}13.求m，n的最小公倍数
cpp
#include<stdio.h>
int main() {
//lcm:lowest common multiple 最小公倍数
int m, n,min;
scanf_s("%d %d", &m, &n);
if (m < n) min = m;
else min = n;
for(int i=min;i<=n*m;i++)
if (i % m == 0 && i % n == 0) {
printf("最小公倍数：%d", i);
break;
}
return 0;
}14.对10个数排序
cpp
#include<stdio.h>
int quick_one_pass(int a[], int low, int high) {
int mid = a[low];
while (low < high) {
while (low < high && a[high] >= mid) --high;
a[low] = a[high];
while (low < high && a[low] <= mid) ++low;
a[high] = a[low];
}
a[low] = mid;
return low;
}
void quicksort(int a[], int low, int high) {
int k;
if (low < high) {
k = quick_one_pass(a, low, high);
quicksort(a, low, k - 1);
quicksort(a, k + 1, high);
}
}
int main() {
//快速排序
int a[10] = { 2,6,4,8,1,9,3,5,7,4 };
quicksort(a, 0, 9);
for (int i = 0; i < 10; i++)
printf("%d ", a[i]);
return 0;
}