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题目
请编写程序,根据给定二叉树的层序序列化结果,重构二叉树,并输出其层序遍历结果。
输入格式:
输入首先给出一个不超 20 的正整数 n,随后一行给出 n 个层序序列的元素。其中键值都是不超过 9 位的正整数,空结点对应符号 #。
输出格式:
输出二叉树的层序遍历结果,每个数字占一行。
输入样例:
11
1 2 3 # 4 5 # # # # #
输出样例:
1
2
3
4
5
代码
cpp
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct TreeNode {
int data;
struct TreeNode *left;
struct TreeNode *right;
} TreeNode;
TreeNode* createNode(int data) {
TreeNode* node = (TreeNode*)malloc(sizeof(TreeNode));
node->data = data;
node->left = NULL;
node->right = NULL;
return node;
}
TreeNode* buildTree(char** tokens, int n) {
if (n == 0 || strcmp(tokens[0], "#") == 0) return NULL;
TreeNode* root = createNode(atoi(tokens[0]));
TreeNode* queue[1000];
int front = 0, rear = 0;
queue[rear++] = root;
int i = 1;
while (i < n && front < rear) {
TreeNode* current = queue[front++];
// 处理左子节点
if (i < n && strcmp(tokens[i], "#") != 0) {
current->left = createNode(atoi(tokens[i]));
queue[rear++] = current->left;
}
i++;
// 处理右子节点
if (i < n && strcmp(tokens[i], "#") != 0) {
current->right = createNode(atoi(tokens[i]));
queue[rear++] = current->right;
}
i++;
}
return root;
}
void levelOrderTraversal(TreeNode* root) {
if (root == NULL) return;
TreeNode* queue[1000];
int front = 0, rear = 0;
queue[rear++] = root;
while (front < rear) {
TreeNode* current = queue[front++];
printf("%d\n", current->data);
if (current->left != NULL) queue[rear++] = current->left;
if (current->right != NULL) queue[rear++] = current->right;
}
}
void freeTree(TreeNode* root) {
if (root == NULL) return;
freeTree(root->left);
freeTree(root->right);
free(root);
}
int main() {
int n;
scanf("%d", &n);
getchar(); // 消耗换行符
char input[1000];
fgets(input, sizeof(input), stdin);
char* tokens[100];
int count = 0;
char* token = strtok(input, " \n");
while (token != NULL && count < n) {
tokens[count++] = token;
token = strtok(NULL, " \n");
}
TreeNode* root = buildTree(tokens, n);
levelOrderTraversal(root);
freeTree(root);
return 0;
}