37. 解数独

编写一个程序,通过填充空格来解决数独问题。

数独的解法需遵循如下规则

  1. 数字 1-9 在每一行只能出现一次。
  2. 数字 1-9 在每一列只能出现一次。
  3. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)

数独部分空格内已填入了数字,空白格用 '.' 表示。

示例 1:

复制代码
输入:board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]
输出:[["5","3","4","6","7","8","9","1","2"],["6","7","2","1","9","5","3","4","8"],["1","9","8","3","4","2","5","6","7"],["8","5","9","7","6","1","4","2","3"],["4","2","6","8","5","3","7","9","1"],["7","1","3","9","2","4","8","5","6"],["9","6","1","5","3","7","2","8","4"],["2","8","7","4","1","9","6","3","5"],["3","4","5","2","8","6","1","7","9"]]
解释:输入的数独如上图所示,唯一有效的解决方案如下所示:

提示:

  • board.length == 9
  • board[i].length == 9
  • board[i][j] 是一位数字或者 '.'
  • 题目数据 保证 输入数独仅有一个
cpp 复制代码
class Solution {
public:
    bool isvaild(int row,int col,char val,vector<vector<char>>& board){
        //row
        for(int i = 0;i < 9;i++){
            if(board[row][i] == val) return false;
        }
        //col
        for(int j = 0;j < 9;j++){
            if(board[j][col] == val) return false;
        }
        //九宫格
        int startx = (row/3)*3; // 假如在第一个九宫格,row/3=0,再*3=0;
        int starty = (col/3)*3; //假如在第二个九宫格,row/3=1,再*3=3; 我直呼nb
        for(int i = startx;i < startx+3;i++){
            for(int j = starty;j < starty+3;j++){
                if(board[i][j] == val) return false;
            }
        }
        return true;
    }
    bool backtracking(vector<vector<char>>& board){
        for(int i = 0;i < board.size();i++){
            for(int j = 0;j < board[0].size();j++){
                //遇到空格
                if(board[i][j] == '.'){
                    for(char a = '1';a <= '9';a++){
                        //判断这里应该填入啥数字合法
                        if(isvaild(i,j,a,board)){
                            board[i][j] = a;
                            //得将这个状态一直返回
                            if(backtracking(board) == true) return true;
                            board[i][j] = '.'; // 回溯
                        }
                    }
                    return false; //填入0-9都不对,都不合法,填错了。
                }
            }
        }
        return true; //填完且填正确了。
    }
    void solveSudoku(vector<vector<char>>& board) {
        backtracking(board);
    }
};
相关推荐
6Hzlia3 分钟前
【Hot 100 刷题计划】 LeetCode 76. 最小覆盖子串 | C++ 滑动窗口题解
c++·算法·leetcode
像素猎人7 分钟前
蓝桥杯OJ2049蓝桥勇士【动态规划】【dp[n]不是符合题意的答案,只是以an结尾的子问题的答案】
c++·算法·蓝桥杯·动态规划·区间dp
羊小猪~~7 分钟前
LLM--SFT简介
python·考研·算法·ai·大模型·llm·微调
广州灵眸科技有限公司19 分钟前
瑞芯微(EASY EAI)RV1126B 人脸98关键点算法识别
开发语言·科技·嵌入式硬件·物联网·算法·php
篮子里的玫瑰23 分钟前
FreeRTOS:信号量与互斥量在DMA串口发送中的实战剖析
stm32·单片机·嵌入式硬件·算法
hughnz24 分钟前
钻头技术持续突飞猛进:地热钻探领域的创新
人工智能·算法
xiaoye-duck31 分钟前
《算法题讲解指南:动态规划算法--子数组系列》--21.乘积最大子数组,22.乘积为正数的最长子数组
c++·算法·动态规划
MicroTech202531 分钟前
突破非幺正动力学瓶颈:MLGO微算法科技量子虚时演化赋能开放量子系统模拟
科技·算法·量子计算
Book思议-32 分钟前
【数据结构】二叉树非递归前中后序遍历详解
数据结构·二叉树非递归前中后序遍历
计算机安禾33 分钟前
【数据结构与算法】第24篇:哈夫曼树与哈夫曼编码
c语言·开发语言·数据结构·c++·算法·visual studio