37. 解数独

编写一个程序,通过填充空格来解决数独问题。

数独的解法需遵循如下规则

  1. 数字 1-9 在每一行只能出现一次。
  2. 数字 1-9 在每一列只能出现一次。
  3. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)

数独部分空格内已填入了数字,空白格用 '.' 表示。

示例 1:

复制代码
输入:board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]
输出:[["5","3","4","6","7","8","9","1","2"],["6","7","2","1","9","5","3","4","8"],["1","9","8","3","4","2","5","6","7"],["8","5","9","7","6","1","4","2","3"],["4","2","6","8","5","3","7","9","1"],["7","1","3","9","2","4","8","5","6"],["9","6","1","5","3","7","2","8","4"],["2","8","7","4","1","9","6","3","5"],["3","4","5","2","8","6","1","7","9"]]
解释:输入的数独如上图所示,唯一有效的解决方案如下所示:

提示:

  • board.length == 9
  • board[i].length == 9
  • board[i][j] 是一位数字或者 '.'
  • 题目数据 保证 输入数独仅有一个
cpp 复制代码
class Solution {
public:
    bool isvaild(int row,int col,char val,vector<vector<char>>& board){
        //row
        for(int i = 0;i < 9;i++){
            if(board[row][i] == val) return false;
        }
        //col
        for(int j = 0;j < 9;j++){
            if(board[j][col] == val) return false;
        }
        //九宫格
        int startx = (row/3)*3; // 假如在第一个九宫格,row/3=0,再*3=0;
        int starty = (col/3)*3; //假如在第二个九宫格,row/3=1,再*3=3; 我直呼nb
        for(int i = startx;i < startx+3;i++){
            for(int j = starty;j < starty+3;j++){
                if(board[i][j] == val) return false;
            }
        }
        return true;
    }
    bool backtracking(vector<vector<char>>& board){
        for(int i = 0;i < board.size();i++){
            for(int j = 0;j < board[0].size();j++){
                //遇到空格
                if(board[i][j] == '.'){
                    for(char a = '1';a <= '9';a++){
                        //判断这里应该填入啥数字合法
                        if(isvaild(i,j,a,board)){
                            board[i][j] = a;
                            //得将这个状态一直返回
                            if(backtracking(board) == true) return true;
                            board[i][j] = '.'; // 回溯
                        }
                    }
                    return false; //填入0-9都不对,都不合法,填错了。
                }
            }
        }
        return true; //填完且填正确了。
    }
    void solveSudoku(vector<vector<char>>& board) {
        backtracking(board);
    }
};
相关推荐
星释10 分钟前
Rust 练习册 67:自定义集合与数据结构实现
数据结构·算法·rust
6***x54510 分钟前
C++在计算机视觉中的图像处理
c++·图像处理·计算机视觉·游戏引擎·logback·milvus
fpcc13 分钟前
跟我学C++中级篇——内存访问违例
c++
E***q53920 分钟前
C++内存对齐优化
开发语言·c++
D_evil__22 分钟前
[C++高频精进] 文件IO:文件操作
c++
前端小L1 小时前
图论专题(十九):DAG上的“关键路径”——极限规划「并行课程 III」
算法·矩阵·深度优先·图论·宽度优先
scx201310041 小时前
20251116 树状DP总结
算法·深度优先·图论
Aspect of twilight1 小时前
LeetCode华为大模型岗刷题
python·leetcode·华为·力扣·算法题
别动哪条鱼1 小时前
MP4转AAC转换器C++
c++·ffmpeg·音视频·aac
2301_807997382 小时前
代码随想录-day47
数据结构·c++·算法·leetcode