LeetCode每日一题——2586. Count the Number of Vowel Strings in Range

文章目录

一、题目

You are given a 0-indexed array of string words and two integers left and right.

A string is called a vowel string if it starts with a vowel character and ends with a vowel character where vowel characters are 'a', 'e', 'i', 'o', and 'u'.

Return the number of vowel strings words[i] where i belongs to the inclusive range [left, right].

Example 1:

Input: words = ["are","amy","u"], left = 0, right = 2

Output: 2

Explanation:

  • "are" is a vowel string because it starts with 'a' and ends with 'e'.
  • "amy" is not a vowel string because it does not end with a vowel.
  • "u" is a vowel string because it starts with 'u' and ends with 'u'.
    The number of vowel strings in the mentioned range is 2.
    Example 2:

Input: words = ["hey","aeo","mu","ooo","artro"], left = 1, right = 4

Output: 3

Explanation:

  • "aeo" is a vowel string because it starts with 'a' and ends with 'o'.
  • "mu" is not a vowel string because it does not start with a vowel.
  • "ooo" is a vowel string because it starts with 'o' and ends with 'o'.
  • "artro" is a vowel string because it starts with 'a' and ends with 'o'.
    The number of vowel strings in the mentioned range is 3.

Constraints:

1 <= words.length <= 1000

1 <= words[i].length <= 10

words[i] consists of only lowercase English letters.

0 <= left <= right < words.length

二、题解

cpp 复制代码
class Solution {
public:
    int vowelStrings(vector<string>& words, int left, int right) {
        unordered_set<char> set = {'a','e','i','o','u'};
        int res = 0;
        for(int i = left;i <= right;i++){
            char front = words[i][0];
            char back = words[i].back();
            if(set.count(front) && set.count(back)) res++;
        }
        return res;
    }
};
相关推荐
MobotStone1 小时前
从金鱼记忆到过目不忘:Transformer 如何让AI真正理解一句话?
算法
lizz312 小时前
C++模板编程:从入门到精通
java·开发语言·c++
炽烈小老头2 小时前
【每天学习一点算法 2025/12/19】二叉树的层序遍历
数据结构·学习·算法
Queenie_Charlie2 小时前
HASH表
数据结构·c++·哈希算法
Xの哲學3 小时前
Linux grep命令:文本搜索的艺术与科学
linux·服务器·算法·架构·边缘计算
soft20015253 小时前
MySQL Buffer Pool深度解析:LRU算法的完美与缺陷
数据库·mysql·算法
superman超哥3 小时前
仓颉语言中锁的实现机制深度剖析与并发实践
c语言·开发语言·c++·python·仓颉
郝学胜-神的一滴3 小时前
OpenGL的glDrawElements函数详解
开发语言·c++·程序人生·游戏·图形渲染
WBluuue3 小时前
AtCoder Beginner Contest 436(ABCDEF)
c++·算法
fie88893 小时前
广义 S 变换(GST)地震信号时频谱
算法