LeetCode //C - 179. Largest Number

179. Largest Number

Given a list of non-negative integers nums, arrange them such that they form the largest number and return it.

Since the result may be very large, so you need to return a string instead of an integer.

Example 1:

Input: nums = [10,2]
Output: "210"

Example 2:

Input: nums = [3,30,34,5,9]
Output: "9534330"

Constraints:
  • 1 <= nums.length <= 100
  • 0 < = n u m s [ i ] < = 1 0 9 0 <= nums[i] <= 10^9 0<=nums[i]<=109

From: LeetCode

Link: 179. Largest Number


Solution:

Ideas:
  1. Convert integers to strings: Since the concatenation of numbers as strings is required, the integers are first converted to strings.

  2. Custom Comparator: A custom comparator function is used to sort these strings. The key idea here is to determine the order of any two strings a and b by comparing the two possible concatenations: a+b and b+a. If a+b is greater than b+a, then a should come before b in the final order, and vice versa.

  3. Sort the strings: Using the custom comparator, the list of strings is sorted in such a way that concatenating them in this order results in the largest possible number.

  4. Concatenate sorted strings: After sorting, the strings are concatenated together to form the final result.

  5. Edge Case Handling: If the largest number is 0, meaning all numbers are zero, the result should simply be "0".

Code:
c 复制代码
int compare(const void *a, const void *b) {
    // Cast the pointers to strings
    const char *str1 = *(const char **)a;
    const char *str2 = *(const char **)b;
    
    // Allocate enough space to hold the two concatenated results
    char option1[22];
    char option2[22];
    
    // Concatenate str1+str2 and str2+str1
    sprintf(option1, "%s%s", str1, str2);
    sprintf(option2, "%s%s", str2, str1);
    
    // Return the comparison result in descending order
    return strcmp(option2, option1);
}

char* largestNumber(int* nums, int numsSize) {
    if (numsSize == 0) return "";

    // Convert numbers to strings
    char **numsStr = (char **)malloc(numsSize * sizeof(char *));
    for (int i = 0; i < numsSize; ++i) {
        numsStr[i] = (char *)malloc(12 * sizeof(char)); // Enough for an integer with max 10 digits and a null terminator
        sprintf(numsStr[i], "%d", nums[i]);
    }

    // Sort the array with custom comparator
    qsort(numsStr, numsSize, sizeof(char *), compare);

    // If the highest number is "0", the entire number is "0"
    if (strcmp(numsStr[0], "0") == 0) {
        // Free allocated memory
        for (int i = 0; i < numsSize; ++i) {
            free(numsStr[i]);
        }
        free(numsStr);
        return "0";
    }

    // Calculate total length for the resulting string
    int totalLength = 0;
    for (int i = 0; i < numsSize; ++i) {
        totalLength += strlen(numsStr[i]);
    }

    // Allocate space for the result string
    char *result = (char *)malloc((totalLength + 1) * sizeof(char));
    result[0] = '\0'; // Initialize to an empty string

    // Concatenate all strings
    for (int i = 0; i < numsSize; ++i) {
        strcat(result, numsStr[i]);
        free(numsStr[i]); // Free the individual string after use
    }

    free(numsStr); // Free the array of string pointers

    return result;
}
相关推荐
折枝寄北5 分钟前
从零开始 | C语言基础刷题DAY1
c语言·开发语言·算法
.ccl33 分钟前
蓝桥杯省赛真题C++B组2024-握手问题
c++·算法·蓝桥杯
arong_xu1 小时前
C++20 新特性总结
算法·c++20
hrrrrb1 小时前
【C语言】指针篇
c语言·数据结构·算法
神里流~霜灭1 小时前
下降路径最⼩和(medium)
数据结构·c++·算法·链表·贪心算法·动态规划
编程绿豆侠1 小时前
力扣HOT100之双指针:11. 盛最多水的容器
算法·leetcode·职场和发展
*.✧屠苏隐遥(ノ◕ヮ◕)ノ*.✧1 小时前
C语言_数据结构总结4:不带头结点的单链表
c语言·开发语言·数据结构·算法·链表·visualstudio·visual studio
a李兆洋2 小时前
力扣 Hot 100 刷题记录 - LRU 缓存
算法·leetcode·缓存
极客代码2 小时前
Linux IPC:System V共享内存汇总整理
linux·c语言·开发语言·并发·共享内存·通信·system v
算法与编程之美2 小时前
冒泡排序
java·开发语言·数据结构·算法·排序算法