代码随想录算法训练营第五十六天 | 图论part06

108. 冗余连接

cpp 复制代码
#include <iostream>
#include <vector>

using namespace std;

void init(vector<int> &father) {
    for (int i = 0; i < father.size(); ++i) {
        father[i] = i;
    }
}

int find(vector<int>& father, int u) {
    if (father[u] == u) return u;
    return father[u] = find(father, father[u]);
}

int isSame(vector<int>& father, int u, int v) {
    u = find(father, u);
    v = find(father, v);
    return u == v;
}

void join(vector<int>& father, int u, int v) {
    u = find(father, u);
    v = find(father, v);
    if (u == v) return;
    father[v] = u;
}
int main()
{
    int n, u, v, resultu, resultv;
    cin >> n;
    vector<int> father(n + 1, 0);
    init(father);
    for (int i = 0; i < n; ++i) {
        cin >> u >> v;
        if (isSame(father, u, v)) {
            resultu = u;
            resultv = v;
        }
        else
            join(father, u, v);
    }
    cout << resultu << " " << resultv << endl;
    return 0;
}

109. 冗余连接II

关键是要能够分出两种情况:

  1. 是不是存在入度为2的点,然后判断哪一条边去掉,还是连通的。在这里也有两种情况,一种是直接删除最后一个边,一种是会形成环。
  2. 是不是存在环
cpp 复制代码
#include <iostream>
#include <vector>

using namespace std;

void init(vector<int>& father) {
    for (int i = 0; i < father.size(); ++i) {
        father[i] = i;
    }
}

int find(vector<int>& father, int u) {
    if (father[u] == u) return u;
    return father[u] = find(father, father[u]);
}

int isSame(vector<int>& father, int u, int v) {
    u = find(father, u);
    v = find(father, v);
    return u == v;
}

void join(vector<int>& father, int u, int v) {
    u = find(father, u);
    v = find(father, v);
    if (u == v) return;
    father[v] = u;
}

bool isTreeAfterRemove(vector<int>& father, const vector<vector<int>>& edges, int deleteEdge) {
    init(father);
    for (int i = 0; i < edges.size(); ++i) {
        if (i == deleteEdge) continue;
        if (isSame(father, edges[i][0], edges[i][1]))
            return false;
        join(father, edges[i][0], edges[i][1]);
    }
    return true;
}

void getRemoveEdge(vector<int>& father, const vector<vector<int>>& edges) {
    init(father);
    for (vector<int> pair : edges) {
        if (isSame(father, pair[0], pair[1])) {
            cout << pair[0] << " " << pair[1] << endl;
            return;
        }
        join(father, pair[0], pair[1]);
    }
}

int main()
{
    int n, u, v;
    cin >> n;
    vector<int> father(n + 1, 0);
    vector<vector<int>> edges;
    vector<int> inDegrees(n + 1, 0);
    for (int i = 0; i < n; ++i) {
        cin >> u >> v;
        inDegrees[v]++;
        edges.emplace_back(vector<int>{u, v});
    }

    vector<int> vec;
    for (int i = n - 1; i >= 0; --i) {
        if (inDegrees[edges[i][1]] == 2)
            vec.push_back(i);
    }
    if (vec.size() > 0) {
        if (isTreeAfterRemove(father, edges, vec[0])) {
            cout << edges[vec[0]][0] << " " << edges[vec[0]][1] << endl;
        }
        else
            cout << edges[vec[1]][0] << " " << edges[vec[1]][1] << endl;
        return 0;
    }
    getRemoveEdge(father, edges);
    return 0;
}
相关推荐
ZPC82101 小时前
docker 镜像备份
人工智能·算法·fpga开发·机器人
ZPC82101 小时前
docker 使用GUI ROS2
人工智能·算法·fpga开发·机器人
琢磨先生David1 小时前
Day1:基础入门·两数之和(LeetCode 1)
数据结构·算法·leetcode
颜酱1 小时前
栈的经典应用:从基础到进阶,解决LeetCode高频栈类问题
javascript·后端·算法
多恩Stone2 小时前
【C++入门扫盲1】C++ 与 Python:类型、编译器/解释器与 CPU 的关系
开发语言·c++·人工智能·python·算法·3d·aigc
生信大杂烩2 小时前
癌症中的“细胞邻域“:解码肿瘤微环境的空间密码 ——Nature Cancer 综述解读
人工智能·算法
蜡笔小马2 小时前
21.Boost.Geometry disjoint、distance、envelope、equals、expand和for_each算法接口详解
c++·算法·boost
m0_531237172 小时前
C语言-数组练习进阶
c语言·开发语言·算法
超级大福宝2 小时前
N皇后问题:经典回溯算法的一些分析
数据结构·c++·算法·leetcode
Wect3 小时前
LeetCode 530. 二叉搜索树的最小绝对差:两种解法详解(迭代+递归)
前端·算法·typescript