原题链接:Leetcode 155. 最小栈
官方解法:辅助栈
cpp
class MinStack {
stack<int> st;
stack<int> minst;
public:
MinStack() {
minst.push(INT_MAX);
}
void push(int val) {
st.push(val);
minst.push(min(minst.top(),val));
}
void pop() {
st.pop();
minst.pop();
}
int top() {
return st.top();
}
int getMin() {
return minst.top();
}
};
/**
* Your MinStack object will be instantiated and called as such:
* MinStack* obj = new MinStack();
* obj->push(val);
* obj->pop();
* int param_3 = obj->top();
* int param_4 = obj->getMin();
*/
一个栈同时保存当前值和栈内最小值
cpp
class MinStack {
stack<pair<int,int>> st;
public:
MinStack() {
st.push({-1,INT_MAX});
}
void push(int val) {
st.push({val,min(getMin(),val)});
}
void pop() {
st.pop();
}
int top() {
return st.top().first;
}
int getMin() {
return st.top().second;
}
};
/**
* Your MinStack object will be instantiated and called as such:
* MinStack* obj = new MinStack();
* obj->push(val);
* obj->pop();
* int param_3 = obj->top();
* int param_4 = obj->getMin();
*/