【力扣练习题】121. 买卖股票的最佳时机

class Solution {

public int maxProfit(int\[\] prices) {

int l = prices.length;

int max = 0;

int minNum = prices0;

for (int i = 0;i< l;i++) {

minNum = Math.min(pricesi, minNum);

max = Math.max(max, (pricesi - minNum));

}

return max;

}

}