第N个泰波那契数
cpp
class Solution {
public:
int tribonacci(int n) {
if (n == 0) {
return 0;
}
if (n <= 2) {
return 1;
}
int dp[n + 1];
dp[0] = 0;
dp[1] = 1;
dp[2] = 1;
for (int i = 3; i <= n; i++) {
dp[i] = dp[i - 1] + dp[i - 2] + dp[i - 3];
}
return dp[n];
}
};
使用最小花费爬楼梯
cpp
class Solution {
public:
int minCostClimbingStairs(vector<int>& cost) {
int cLen = cost.size();
int minCost[cLen + 1];
minCost[0] = 0;
minCost[1] = 0;
for (int i = 2; i <= cLen; i++) {
minCost[i] = min(minCost[i - 1] + cost[i - 1], minCost[i - 2] + cost[i - 2]);
}
return minCost[cLen];
}
};
打家劫舍
cpp
class Solution {
public:
int rob(vector<int>& nums) {
int n = nums.size();
if (n == 1) {
return nums[0];
}
if (n == 2) {
return max(nums[0], nums[1]);
}
int dp[n];
dp[0] = nums[0];
dp[1] = max(nums[0],nums[1]);
for (int i = 2; i < n; i++) {
dp[i] = max(dp[i - 1], dp[i - 2] + nums[i]);
}
return dp[n - 1];
}
};
多米诺和托米诺平铺
cpp
class Solution {
public:
int numTilings(int n) {
if (n <= 2) {
return n;
}
vector<long long> f(n + 1);
f[0] = 1;
f[1] = 1;
f[2] = 2;
long long y = f[0];
for (int i = 3; i <= n; i++) {
f[i] = (f[i - 1] + f[i - 2] + 2 * y) % (1000000007);
y += f[i - 2];
}
return f[n];
}
};