面试经典150题——Day18

文章目录

一、题目

12. Integer to Roman

Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.

Symbol Value

I 1

V 5

X 10

L 50

C 100

D 500

M 1000

For example, 2 is written as II in Roman numeral, just two one's added together. 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:

I can be placed before V (5) and X (10) to make 4 and 9.

X can be placed before L (50) and C (100) to make 40 and 90.

C can be placed before D (500) and M (1000) to make 400 and 900.

Given an integer, convert it to a roman numeral.

Example 1:

Input: num = 3

Output: "III"

Explanation: 3 is represented as 3 ones.

Example 2:

Input: num = 58

Output: "LVIII"

Explanation: L = 50, V = 5, III = 3.

Example 3:

Input: num = 1994

Output: "MCMXCIV"

Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.

Constraints:

1 <= num <= 3999

题目来源: leetcode

二、题解

由于num的范围在1~3999之间,因此可以直接使用硬编码的方式解决

cpp 复制代码
class Solution {
public:
    string intToRoman(int num) {
        string thousands[] = {"","M","MM","MMM"};
        string hundreds[] = {"","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"};
        string tens[] = {"","X","XX","XXX","XL","L","LX","LXX","LXXX","XC"};
        string ones[] = {"","I","II","III","IV","V","VI","VII","VIII","IX"};
        string res = thousands[num / 1000] + hundreds[(num % 1000) / 100] + tens[(num % 100) / 10] + ones[num % 10];
        return res;
    }
};
相关推荐
HXhlx26 分钟前
CART决策树基本原理
算法·机器学习
Lee川1 小时前
优雅进化的JavaScript:从ES6+新特性看现代前端开发范式
javascript·面试
Wect1 小时前
LeetCode 210. 课程表 II 题解:Kahn算法+DFS 双解法精讲
前端·算法·typescript
颜酱2 小时前
单调队列:滑动窗口极值问题的最优解(通用模板版)
javascript·后端·算法
肆忆_4 小时前
# 用 5 个问题学懂 C++ 虚函数(入门级)
c++
Lee川4 小时前
从异步迷雾到优雅流程:JavaScript异步编程与内存管理的现代化之旅
javascript·面试
晴殇i6 小时前
揭秘JavaScript中那些“不冒泡”的DOM事件
前端·javascript·面试
绝无仅有7 小时前
Redis过期删除与内存淘汰策略详解
后端·面试·架构
绝无仅有7 小时前
Redis大Key问题排查与解决方案全解析
后端·面试·架构
AAA梅狸猫8 小时前
Looper.loop() 循环机制
面试