【LeetCode: 36. 有效的数独 + 模拟】

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| 🚀 算法题 🚀 |

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🍔 目录

    • [🚩 题目链接](#🚩 题目链接)
    • [⛲ 题目描述](#⛲ 题目描述)
    • [🌟 求解思路&实现代码&运行结果](#🌟 求解思路&实现代码&运行结果)
      • [⚡ 模拟](#⚡ 模拟)
        • [🥦 求解思路](#🥦 求解思路)
        • [🥦 实现代码](#🥦 实现代码)
        • [🥦 运行结果](#🥦 运行结果)
    • [💬 共勉](#💬 共勉)

🚩 题目链接

⛲ 题目描述

请你判断一个 9 x 9 的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。

数字 1-9 在每一行只能出现一次。

数字 1-9 在每一列只能出现一次。

数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)

注意:

一个有效的数独(部分已被填充)不一定是可解的。

只需要根据以上规则,验证已经填入的数字是否有效即可。

空白格用 '.' 表示。

示例 1:

输入:board =

\["5","3",".",".","7",".",".",".","."

,["6",".",".","1","9","5",".",".","."]

,[".","9","8",".",".",".",".","6","."]

,["8",".",".",".","6",".",".",".","3"]

,["4",".",".","8",".","3",".",".","1"]

,["7",".",".",".","2",".",".",".","6"]

,[".","6",".",".",".",".","2","8","."]

,[".",".",".","4","1","9",".",".","5"]

,[".",".",".",".","8",".",".","7","9"]]

输出:true

示例 2:

输入:board =

\["8","3",".",".","7",".",".",".","."

,["6",".",".","1","9","5",".",".","."]

,[".","9","8",".",".",".",".","6","."]

,["8",".",".",".","6",".",".",".","3"]

,["4",".",".","8",".","3",".",".","1"]

,["7",".",".",".","2",".",".",".","6"]

,[".","6",".",".",".",".","2","8","."]

,[".",".",".","4","1","9",".",".","5"]

,[".",".",".",".","8",".",".","7","9"]]

输出:false

解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。

提示:

board.length == 9

board[i].length == 9

board[i][j] 是一位数字(1-9)或者 '.'

🌟 求解思路&实现代码&运行结果


⚡ 模拟

🥦 求解思路
  1. 根据题目给定的规则模拟即可,在模拟过程中开辟3个二维数组分别表示行、列、3*3单元格,在某一行、列、第几个单元格上此时被数字x填充的标记。
  2. 有了基本的思路,接下来我们就来通过代码来实现一下。
🥦 实现代码
java 复制代码
class Solution {
    public static boolean isValidSudoku(char[][] board) {
        boolean[][] row = new boolean[9][10];
        boolean[][] col = new boolean[9][10];
        boolean[][] bucket = new boolean[9][10];
        for (int i = 0; i < 9; i++) {
            for (int j = 0; j < 9; j++) {
                int bid = 3 * (i / 3) + (j / 3);
                if (board[i][j] != '.') {
                    int num = board[i][j] - '0';
                    if (row[i][num] || col[j][num] || bucket[bid][num]) {
                        return false;
                    }
                    row[i][num] = true;
                    col[j][num] = true;
                    bucket[bid][num] = true;
                }
            }
        }
        return true;
    }

}
🥦 运行结果

💬 共勉

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| 最后,我想和大家分享一句一直激励我的座右铭,希望可以与大家共勉! |

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