LeetCode //C - 23. Merge k Sorted Lists

23. Merge k Sorted Lists

You are given an array of k linked-lists lists, each linked-list is sorted in ascending order.

Merge all the linked-lists into one sorted linked-list and return it.

Example 1:

Input: lists = [[1,4,5],[1,3,4],[2,6]]
Output: [1,1,2,3,4,4,5,6]
Explanation: The linked-lists are:

1-\>4-\>5, 1-\>3-\>4, 2-\>6

merging them into one sorted list:

1->1->2->3->4->4->5->6

Example 2:

Input: lists = []
Output: []

Example 3:

Input: lists = [[]]
Output: []

Constraints:
  • k == lists.length
  • 0 <= k <= 1 0 4 10^4 104
  • 0 <= lists[i].length <= 500
  • − 1 0 4 < = l i s t s [ i ] [ j ] < = 1 0 4 -10^4 <= lists[i][j] <= 10^4 −104<=lists[i][j]<=104
  • lists[i] is sorted in ascending order.
  • The sum of lists[i].length will not exceed 1 0 4 10^4 104.

From: LeetCode

Link: 23. Merge k Sorted Lists


Solution:

Ideas:

Main Idea:

  1. Divide: If you have k linked lists, split them into two groups of k/2 linked lists each.
  2. Conquer: Recursively merge the linked lists in each group.
  3. Merge: After the recursive merge, you'll have two merged lists. Now, merge these two lists into one.
    This approach is akin to the merge step in "merge sort" but applied to linked lists.

Detailed Explanation:

  1. mergeTwoLists Function:

    This function is a basic utility to merge two individual sorted linked lists (l1 and l2). If one list is empty, it returns the other. Otherwise, it compares the current nodes' values of the two lists and selects the smaller one, then continues merging with the rest.

  2. mergeKListsHelper Function:

    This is the recursive function that embodies the divide-and-conquer logic:

  • Base Cases:
    • If start > end, there are no lists to merge, so return NULL.
    • If start == end, there's only one list to consider, so return that list.
  • Recursive Divide & Merge:
    • Find the midpoint of the current range of linked lists (mid).
    • Recursively merge the left half (from start to mid).
    • Recursively merge the right half (from mid + 1 to end).
    • Merge the two halves using mergeTwoLists.
  1. mergeKLists Function:
    This is the main function which acts as an initiator. It starts the recursive merge process with the entire range of linked lists (from 0 to listsSize - 1).
Code:
c 复制代码
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */
struct ListNode* mergeTwoLists(struct ListNode* l1, struct ListNode* l2) {
    if (!l1) return l2;
    if (!l2) return l1;

    if (l1->val < l2->val) {
        l1->next = mergeTwoLists(l1->next, l2);
        return l1;
    } else {
        l2->next = mergeTwoLists(l1, l2->next);
        return l2;
    }
}

struct ListNode* mergeKListsHelper(struct ListNode** lists, int start, int end) {
    if (start > end) return NULL;
    if (start == end) return lists[start];

    int mid = start + (end - start) / 2;

    struct ListNode* left = mergeKListsHelper(lists, start, mid);
    struct ListNode* right = mergeKListsHelper(lists, mid + 1, end);

    return mergeTwoLists(left, right);
}

struct ListNode* mergeKLists(struct ListNode** lists, int listsSize) {
    if (listsSize == 0) return NULL;
    return mergeKListsHelper(lists, 0, listsSize - 1);
}
相关推荐
NAGNIP6 小时前
一文搞懂树模型与集成模型
算法·面试
NAGNIP6 小时前
万字长文!一文搞懂监督学习中的分类模型!
算法·面试
技术狂人1686 小时前
工业大模型工程化部署实战!4 卡 L40S 高可用集群(动态资源调度 + 监控告警 + 国产化适配)
人工智能·算法·面试·职场和发展·vllm
D_FW7 小时前
数据结构第六章:图
数据结构·算法
你怎么知道我是队长7 小时前
C语言---头文件
c语言·开发语言
a程序小傲7 小时前
京东Java面试被问:动态规划的状态压缩和优化技巧
java·开发语言·mysql·算法·adb·postgresql·深度优先
自学不成才7 小时前
深度复盘:一次flutter应用基于内存取证的黑盒加密破解实录并完善算法推理助手
c++·python·算法·数据挖掘
3有青年8 小时前
nios ii 中 ‘ALT_CPU_FREQ‘ could not be resolved的分析和解决办法
c语言·fpga开发
June`8 小时前
全排列与子集算法精解
算法·leetcode·深度优先