LeetCode //C - 23. Merge k Sorted Lists

23. Merge k Sorted Lists

You are given an array of k linked-lists lists, each linked-list is sorted in ascending order.

Merge all the linked-lists into one sorted linked-list and return it.

Example 1:

Input: lists = [[1,4,5],[1,3,4],[2,6]]
Output: [1,1,2,3,4,4,5,6]
Explanation: The linked-lists are:

[

1->4->5,

1->3->4,

2->6

]

merging them into one sorted list:

1->1->2->3->4->4->5->6

Example 2:

Input: lists = []
Output: []

Example 3:

Input: lists = [[]]
Output: []

Constraints:
  • k == lists.length
  • 0 <= k <= 1 0 4 10^4 104
  • 0 <= lists[i].length <= 500
  • − 1 0 4 < = l i s t s [ i ] [ j ] < = 1 0 4 -10^4 <= lists[i][j] <= 10^4 −104<=lists[i][j]<=104
  • lists[i] is sorted in ascending order.
  • The sum of lists[i].length will not exceed 1 0 4 10^4 104.

From: LeetCode

Link: 23. Merge k Sorted Lists


Solution:

Ideas:

Main Idea:

  1. Divide: If you have k linked lists, split them into two groups of k/2 linked lists each.
  2. Conquer: Recursively merge the linked lists in each group.
  3. Merge: After the recursive merge, you'll have two merged lists. Now, merge these two lists into one.
    This approach is akin to the merge step in "merge sort" but applied to linked lists.

Detailed Explanation:

  1. mergeTwoLists Function:

    This function is a basic utility to merge two individual sorted linked lists (l1 and l2). If one list is empty, it returns the other. Otherwise, it compares the current nodes' values of the two lists and selects the smaller one, then continues merging with the rest.

  2. mergeKListsHelper Function:

    This is the recursive function that embodies the divide-and-conquer logic:

  • Base Cases:
    • If start > end, there are no lists to merge, so return NULL.
    • If start == end, there's only one list to consider, so return that list.
  • Recursive Divide & Merge:
    • Find the midpoint of the current range of linked lists (mid).
    • Recursively merge the left half (from start to mid).
    • Recursively merge the right half (from mid + 1 to end).
    • Merge the two halves using mergeTwoLists.
  1. mergeKLists Function:
    This is the main function which acts as an initiator. It starts the recursive merge process with the entire range of linked lists (from 0 to listsSize - 1).
Code:
c 复制代码
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */
struct ListNode* mergeTwoLists(struct ListNode* l1, struct ListNode* l2) {
    if (!l1) return l2;
    if (!l2) return l1;

    if (l1->val < l2->val) {
        l1->next = mergeTwoLists(l1->next, l2);
        return l1;
    } else {
        l2->next = mergeTwoLists(l1, l2->next);
        return l2;
    }
}

struct ListNode* mergeKListsHelper(struct ListNode** lists, int start, int end) {
    if (start > end) return NULL;
    if (start == end) return lists[start];

    int mid = start + (end - start) / 2;

    struct ListNode* left = mergeKListsHelper(lists, start, mid);
    struct ListNode* right = mergeKListsHelper(lists, mid + 1, end);

    return mergeTwoLists(left, right);
}

struct ListNode* mergeKLists(struct ListNode** lists, int listsSize) {
    if (listsSize == 0) return NULL;
    return mergeKListsHelper(lists, 0, listsSize - 1);
}
相关推荐
计算机小白一个4 小时前
蓝桥杯 Java B 组之设计 LRU 缓存
java·算法·蓝桥杯
万事可爱^4 小时前
HDBSCAN:密度自适应的层次聚类算法解析与实践
算法·机器学习·数据挖掘·聚类·hdbscan
李白同学5 小时前
【C语言】结构体内存对齐问题
c语言·开发语言
楼台的春风6 小时前
【MCU驱动开发概述】
c语言·驱动开发·单片机·嵌入式硬件·mcu·自动驾驶·嵌入式
大数据追光猿6 小时前
Python应用算法之贪心算法理解和实践
大数据·开发语言·人工智能·python·深度学习·算法·贪心算法
Dream it possible!6 小时前
LeetCode 热题 100_在排序数组中查找元素的第一个和最后一个位置(65_34_中等_C++)(二分查找)(一次二分查找+挨个搜索;两次二分查找)
c++·算法·leetcode
夏末秋也凉6 小时前
力扣-回溯-46 全排列
数据结构·算法·leetcode
南宫生6 小时前
力扣每日一题【算法学习day.132】
java·学习·算法·leetcode
柠石榴6 小时前
【练习】【回溯No.1】力扣 77. 组合
c++·算法·leetcode·回溯
Leuanghing6 小时前
【Leetcode】11. 盛最多水的容器
python·算法·leetcode