LeetCode //C - 23. Merge k Sorted Lists

23. Merge k Sorted Lists

You are given an array of k linked-lists lists, each linked-list is sorted in ascending order.

Merge all the linked-lists into one sorted linked-list and return it.

Example 1:

Input: lists = [[1,4,5],[1,3,4],[2,6]]
Output: [1,1,2,3,4,4,5,6]
Explanation: The linked-lists are:

1-\>4-\>5, 1-\>3-\>4, 2-\>6

merging them into one sorted list:

1->1->2->3->4->4->5->6

Example 2:

Input: lists = []
Output: []

Example 3:

Input: lists = [[]]
Output: []

Constraints:
  • k == lists.length
  • 0 <= k <= 1 0 4 10^4 104
  • 0 <= lists[i].length <= 500
  • − 1 0 4 < = l i s t s [ i ] [ j ] < = 1 0 4 -10^4 <= lists[i][j] <= 10^4 −104<=lists[i][j]<=104
  • lists[i] is sorted in ascending order.
  • The sum of lists[i].length will not exceed 1 0 4 10^4 104.

From: LeetCode

Link: 23. Merge k Sorted Lists


Solution:

Ideas:

Main Idea:

  1. Divide: If you have k linked lists, split them into two groups of k/2 linked lists each.
  2. Conquer: Recursively merge the linked lists in each group.
  3. Merge: After the recursive merge, you'll have two merged lists. Now, merge these two lists into one.
    This approach is akin to the merge step in "merge sort" but applied to linked lists.

Detailed Explanation:

  1. mergeTwoLists Function:

    This function is a basic utility to merge two individual sorted linked lists (l1 and l2). If one list is empty, it returns the other. Otherwise, it compares the current nodes' values of the two lists and selects the smaller one, then continues merging with the rest.

  2. mergeKListsHelper Function:

    This is the recursive function that embodies the divide-and-conquer logic:

  • Base Cases:
    • If start > end, there are no lists to merge, so return NULL.
    • If start == end, there's only one list to consider, so return that list.
  • Recursive Divide & Merge:
    • Find the midpoint of the current range of linked lists (mid).
    • Recursively merge the left half (from start to mid).
    • Recursively merge the right half (from mid + 1 to end).
    • Merge the two halves using mergeTwoLists.
  1. mergeKLists Function:
    This is the main function which acts as an initiator. It starts the recursive merge process with the entire range of linked lists (from 0 to listsSize - 1).
Code:
c 复制代码
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */
struct ListNode* mergeTwoLists(struct ListNode* l1, struct ListNode* l2) {
    if (!l1) return l2;
    if (!l2) return l1;

    if (l1->val < l2->val) {
        l1->next = mergeTwoLists(l1->next, l2);
        return l1;
    } else {
        l2->next = mergeTwoLists(l1, l2->next);
        return l2;
    }
}

struct ListNode* mergeKListsHelper(struct ListNode** lists, int start, int end) {
    if (start > end) return NULL;
    if (start == end) return lists[start];

    int mid = start + (end - start) / 2;

    struct ListNode* left = mergeKListsHelper(lists, start, mid);
    struct ListNode* right = mergeKListsHelper(lists, mid + 1, end);

    return mergeTwoLists(left, right);
}

struct ListNode* mergeKLists(struct ListNode** lists, int listsSize) {
    if (listsSize == 0) return NULL;
    return mergeKListsHelper(lists, 0, listsSize - 1);
}
相关推荐
晚霞的不甘20 分钟前
Flutter for OpenHarmony 可视化教学:A* 寻路算法的交互式演示
人工智能·算法·flutter·架构·开源·音视频
望舒51323 分钟前
代码随想录day25,回溯算法part4
java·数据结构·算法·leetcode
C++ 老炮儿的技术栈39 分钟前
Qt 编写 TcpClient 程序 详细步骤
c语言·开发语言·数据库·c++·qt·算法
KYGALYX43 分钟前
逻辑回归详解
算法·机器学习·逻辑回归
铉铉这波能秀1 小时前
LeetCode Hot100数据结构背景知识之集合(Set)Python2026新版
数据结构·python·算法·leetcode·哈希算法
参.商.1 小时前
【Day 27】121.买卖股票的最佳时机 122.买卖股票的最佳时机II
leetcode·golang
踢足球09291 小时前
寒假打卡:2026-2-8
数据结构·算法
IT猿手1 小时前
基于强化学习的多算子差分进化路径规划算法QSMODE的机器人路径规划问题研究,提供MATLAB代码
算法·matlab·机器人
千逐-沐风1 小时前
SMU-ACM2026冬训周报3rd
算法
wangjialelele1 小时前
Linux下的IO操作以及ext系列文件系统
linux·运维·服务器·c语言·c++·个人开发