LeetCode39. Combination Sum

文章目录

一、题目

Given an array of distinct integers candidates and a target integer target, return a list of all unique combinations of candidates where the chosen numbers sum to target. You may return the combinations in any order.

The same number may be chosen from candidates an unlimited number of times. Two combinations are unique if the

frequency

of at least one of the chosen numbers is different.

The test cases are generated such that the number of unique combinations that sum up to target is less than 150 combinations for the given input.

Example 1:

Input: candidates = [2,3,6,7], target = 7

Output: [[2,2,3],[7]]

Explanation:

2 and 3 are candidates, and 2 + 2 + 3 = 7. Note that 2 can be used multiple times.

7 is a candidate, and 7 = 7.

These are the only two combinations.

Example 2:

Input: candidates = [2,3,5], target = 8

Output: [[2,2,2,2],[2,3,3],[3,5]]

Example 3:

Input: candidates = [2], target = 1

Output: []

Constraints:

1 <= candidates.length <= 30

2 <= candidates[i] <= 40

All elements of candidates are distinct.

1 <= target <= 40

二、题解

cpp 复制代码
class Solution {
public:
    vector<vector<int>> res;
    vector<int> tmp;
    void backtracking(vector<int>& candidates,int target,int sum,int startIndex){
        if(sum > target) return;
        if(sum == target){
            res.push_back(tmp);
            return;
        }
        for(int i = startIndex;i < candidates.size();i++){
            tmp.push_back(candidates[i]);
            sum += candidates[i];
            backtracking(candidates,target,sum,i);
            sum -= candidates[i];
            tmp.pop_back();
        }
    }
    vector<vector<int>> combinationSum(vector<int>& candidates, int target) {
        backtracking(candidates,target,0,0);
        return res;
    }
};
相关推荐
笑口常开xpr3 分钟前
数 据 结 构 进 阶:哨 兵 位 的 头 结 点 如 何 简 化 链 表 操 作
数据结构·链表·哨兵位的头节点
BUG收容所所长40 分钟前
栈的奇妙世界:从冰棒到算法的华丽转身
前端·javascript·算法
愚润求学42 分钟前
【C++】类型转换
开发语言·c++
XRZaaa1 小时前
常见排序算法详解与C语言实现
c语言·算法·排序算法
@我漫长的孤独流浪1 小时前
数据结构测试模拟题(4)
数据结构·c++·算法
智驱力人工智能1 小时前
智慧零售管理中的客流统计与属性分析
人工智能·算法·边缘计算·零售·智慧零售·聚众识别·人员计数
csdnzzt1 小时前
从内存角度透视现代C++关键特性
c++
jie188945758662 小时前
C++ 中的 const 知识点详解,c++和c语言区别
java·c语言·c++
明月*清风2 小时前
c++ —— 内存管理
开发语言·c++
WindSearcher2 小时前
大模型微调相关知识
后端·算法