面试经典150题——Day34

文章目录

一、题目

36. Valid Sudoku

Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

Each row must contain the digits 1-9 without repetition.

Each column must contain the digits 1-9 without repetition.

Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.

Note:

A Sudoku board (partially filled) could be valid but is not necessarily solvable.

Only the filled cells need to be validated according to the mentioned rules.

Example 1:

Input: board =

[["5","3",".",".","7",".",".",".","."]

,["6",".",".","1","9","5",".",".","."]

,[".","9","8",".",".",".",".","6","."]

,["8",".",".",".","6",".",".",".","3"]

,["4",".",".","8",".","3",".",".","1"]

,["7",".",".",".","2",".",".",".","6"]

,[".","6",".",".",".",".","2","8","."]

,[".",".",".","4","1","9",".",".","5"]

,[".",".",".",".","8",".",".","7","9"]]

Output: true

Example 2:

Input: board =

[["8","3",".",".","7",".",".",".","."]

,["6",".",".","1","9","5",".",".","."]

,[".","9","8",".",".",".",".","6","."]

,["8",".",".",".","6",".",".",".","3"]

,["4",".",".","8",".","3",".",".","1"]

,["7",".",".",".","2",".",".",".","6"]

,[".","6",".",".",".",".","2","8","."]

,[".",".",".","4","1","9",".",".","5"]

,[".",".",".",".","8",".",".","7","9"]]

Output: false

Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.

Constraints:

board.length == 9

board[i].length == 9

board[i][j] is a digit 1-9 or '.'.

题目来源: leetcode

二、题解

我自己的笨方法

cpp 复制代码
class Solution {
public:
    bool isValidSudoku(vector<vector<char>>& board) {
        unordered_map<char,int> map;
        //遍历行
        for(int i = 0;i < 9;i++){
            //清除上行数据
            map.clear();
            for(int j = 0;j < 9;j++){
                char c = board[i][j];
                if(c != '.'){
                    if(map[c] == 0) map[c]++;
                    else if(map[c] == 1) return false;
                }
            }
        }
        //遍历列
        for(int j = 0;j < 9;j++){
            map.clear();
            for(int i = 0;i < 9;i++){
                char c = board[i][j];
                if(c != '.'){
                    if(map[c] == 0) map[c]++;
                    else if(map[c] == 1) return false;
                }
            }
        }
        //遍历3x3宫格
        for(int i = 0;i < 9;i += 3){
            for(int j = 0;j < 9;j += 3){
                map.clear();
                for(int k = i;k < i + 3;k++){
                    for(int m = j;m < j + 3;m++){
                        char c = board[k][m];
                        if(c != '.'){
                            if(map[c] == 0) map[c]++;
                            else if(map[c] == 1) return false;
                        }
                    }
                }
            }
        }
        return true;
    }
};

答案的好方法

cpp 复制代码
class Solution {
public:
    bool isValidSudoku(vector<vector<char>>& board) {
        int rows[9][9];
        int columns[9][9];
        int subboxes[3][3][9];
        
        memset(rows,0,sizeof(rows));
        memset(columns,0,sizeof(columns));
        memset(subboxes,0,sizeof(subboxes));
        for (int i = 0; i < 9; i++) {
            for (int j = 0; j < 9; j++) {
                char c = board[i][j];
                if (c != '.') {
                    int index = c - '0' - 1;
                    rows[i][index]++;
                    columns[j][index]++;
                    subboxes[i / 3][j / 3][index]++;
                    if (rows[i][index] > 1 || columns[j][index] > 1 || subboxes[i / 3][j / 3][index] > 1) {
                        return false;
                    }
                }
            }
        }
        return true;
    }
};
相关推荐
Mr.Wang80919 分钟前
条款23:宁以non-member、non-friend替换member函数
开发语言·c++
以卿a2 小时前
C++ 模板初阶
开发语言·c++
计算机小白一个6 小时前
蓝桥杯 Java B 组之设计 LRU 缓存
java·算法·蓝桥杯
万事可爱^7 小时前
HDBSCAN:密度自适应的层次聚类算法解析与实践
算法·机器学习·数据挖掘·聚类·hdbscan
黑不溜秋的7 小时前
C++ 设计模式 - 策略模式
c++·设计模式·策略模式
大数据追光猿9 小时前
Python应用算法之贪心算法理解和实践
大数据·开发语言·人工智能·python·深度学习·算法·贪心算法
Dream it possible!9 小时前
LeetCode 热题 100_在排序数组中查找元素的第一个和最后一个位置(65_34_中等_C++)(二分查找)(一次二分查找+挨个搜索;两次二分查找)
c++·算法·leetcode
夏末秋也凉9 小时前
力扣-回溯-46 全排列
数据结构·算法·leetcode
南宫生9 小时前
力扣每日一题【算法学习day.132】
java·学习·算法·leetcode
柠石榴9 小时前
【练习】【回溯No.1】力扣 77. 组合
c++·算法·leetcode·回溯